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3 years ago

5

What is it called when objects become positively charged when they lose electrons and negatively charged when they gain electron

s *
a.Electricity
b.Electrons
c.Electric Charge

2 answers:

AfilCa [17]3 years ago

6 0

It would be c electric charge

Alexeev081 [22]3 years ago

4 0

It is c: electric charge

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Dierdre drew a diagram to compare the three types of mirrors.

Sholpan [36]

<em>Labels that belong in the marked ares X, Y & Z include;</em>

X: Curves outward

Y: Image may be smaller than object

Z: Image is always virtual

<u>Since the rays never meet, the images formed by convex mirrors are always virtual and smaller than the object, and since they are smaller, the images appear to be further than they actually are.</u>

8 0

3 years ago

PLEASE HELP QUICKLY!!! <br> what happens to the motion of objects when they hit each other?

Monica [59]

Answer:

When two objects in motion hit each other they experience forces that are equal in magnitude and opposite in direction. This force causes one of the objects to speed up or gain momentum and other to slow down or lose momentum.

7 0

3 years ago

One strategy in a snowball fight is to throw a snowball at a high angle over level ground. Then, while your opponent is watching

agasfer [191]

Answer:

22.5°

Explanation:

<u>Short answer</u>: The trajectories will hit the same target when the projectile is launched at complementary angles. The second angle is 90° -67.5° = 22.5°.

__

<u>Longer answer</u>: The horizontal speed of the snowball launched at angle α with speed s is ...

vh = s·cos(α)

Then the horizontal distance at time t is ...

x = vh·t

and the time taken to get to some distance x is ...

t = x/vh = x/(s·cos(α))

The equation for the vertical motion of the projectile is ...

y = -4.9t² +s·sin(α)·t

Substituting the above expression for t, we have y in terms of x:

y = -4.9x²/(s·cos(α))² +(s·sin(α)·x)/(s·cos(α))

Factoring gives ...

y = (x/(cos(α))(-4.9x/(s²·cos(α)) +sin(α))

The height y will be zero at x=0 and at ...

0 = -4.9x/(s²·cos(α)) +sin(α)

x = s²·sin(α)·cos(α)/4.9 = (s²/9.8)sin(2α)

So, for some alternate angle β, we want ...

sin(2α) = sin(2β)

We know this will be the case for ...

2β = 180° -2α

β = 90° -α

The second snowball should be thrown at an angle of 90°-67.5° = 22.5° to make it hit the same point as the first.

3 0

3 years ago

A 1,500 kg car’s speed changes from 30 m/s to 15 m/s after the brakes are applied. Calculate the work done onto the car from the

HACTEHA [7]

The work done onto the car is 506,250 J

The work done on a system implies an increase in the internal energy of the system as a result of some forces acting on the system from the outside.

From the parameters given:

The mass of the car = 1500 kg
The initial speed = 30 m/s
The final speed = 15 m/s

The work done onto the car refers to the change in the kinetic energy (i.e. ΔK.E)

$\mathbf{=\dfrac{1}{2} mv_1^2 -\dfrac{1}{2} mv_2^2}$

$\mathbf{=\dfrac{1}{2} m(v_1^2 - v_2^2)}$

$\mathbf{=\dfrac{1}{2} \times 1500 \times (30^2 - 15^2)}$

= 506,250 J

Therefore, we can conclude that the work done on the car is 506,250 J

Learn more about work done here:

brainly.com/question/18762601

7 0

3 years ago

You push a 50 kg wooden box across a wooden floor at a constant speed of 1.0 m/s. The coefficient of kinetic friction is 0.15. N

WARRIOR [948]

Answer:

0.68 seconds

Explanation:

Data provided in the question:

Mass of the box = 50 kg

Speed of the box = 1.0 m/s

Coefficient of friction, μ = 0.15

Now,

Force applied = μmg

Here,

g is the acceleration due to gravity = 9.8 m/s²

Thus,

F = 0.15 × 50 × 9.8

= 73.5 N

Also,

Force = Mass × Acceleration

thus,

73.5 N = 50 × a

or

a = 1.47 m/s²

After doubling the speed

Final speed = 2 × Initial speed

= 2 × 1 m/s

= 2 m/s

Also,

Acceleration = [change in speed] ÷ Time

or

1.47 = [ 2 - 1 ] ÷ Time

or

Time = 1 ÷ 1.47

or

Time = 0.68 seconds

6 0

4 years ago