Answer:
peat them with my dislocated legs
B. to show that there was conflict between what scientists were observing about the universe and what religion taught them
Answer:
1.school and community helps in growth and development of you social health as when u learn how to be compatible with the people around you, you will do better in life
2. by trying and solving
by not giving
by innovating
by being motivated
BY KNOWING THAT U CAN DO IT
Data:

n (Wave node)
V (Wave belly)
L (Wave length)
<span>The number of bells is equal to the number of the harmonic emitted by the string.
</span>

Wire 2 → 2º Harmonic → n = 2







Wire 1 → 1º Harmonic or Fundamental rope → n = 1



If, We have:
V = 42L
Soon:



Answer:
<span>The fundamental frequency of the string:
</span>
21 Hz
Okay! Thank you for this knowledge