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hoa [83]
2 years ago
13

What is the relationship between Newton's first law of motion and inertia?​

Physics
1 answer:
adelina 88 [10]2 years ago
4 0

Explanation: Newton's first law of motion states that a body at rest remains at rest, or, if in motion, remains in motion at a constant velocity unless acted on by a net external force. This is also known as the law of inertia. Inertia is the tendency of an object to remain at rest or remain in motion.

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3rd picture straight line going up right

Explanation:

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3 years ago
List the 5 Greek variables used to measure rotational motion and their counterparts for translational motion
Leni [432]

Explanation:

pizs cake and they dont

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3 years ago
Which of the following represents a chemical property of hydrogen gas? A) It is gaseous at room temperature. B) It is less dense
ehidna [41]

Answer:

C) It reacts explosively with oxygen.

Explanation:

Physical properties are usually those that can be observed using our senses such as color, luster, freezing point, boiling point, melting point, density, hardness and odor.

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3 0
3 years ago
The steering wheel of a car has a radius of 0.19 m, and the steering wheel of a truck has a radius of 0.25 m. The same force is
kodGreya [7K]

Answer:

\frac{T_t}{T_c} = 1.32

Explanation:

The torque applied on an object can be calculated by the following formula:

T = Fr

where,

T = Torque

F = Applied Force

r = radius of the wheel

For car wheel:

T_c = Fr_c\\

For truck wheel:

T_t = Fr_t

Dividing both:

\frac{T_t}{T_c} = \frac{Fr_t}{Fr_c}

for the same force applied on both wheels:

\frac{T_t}{T_c} = \frac{r_t}{r_c} \\

where,

rt = radius of the truck steering wheel = 0.25 m

rc = radius of the car steering wheel = 0.19 m

Therefore,

\frac{T_t}{T_c} = \frac{0.25\ m}{0.19\ m} \\

\frac{T_t}{T_c} = 1.32

8 0
3 years ago
A laser beam is incident on two slits with a separation of 0.230 mm, and a screen is placed 4.75 m from the slits. If the bright
Mariulka [41]

Answer:

7.55\times 10^{-7} m

Explanation:

We are given that

d=0.23 mm=0.23\times 10^{-3} m

1mm=10^{-3} m

Screen is placed  from the slits at distance ,L=4.75 m

The bright interference fringes on the screen are separated  by 1.56 cm.

\Delta y=1.56 cm=1.56\times 10^{-2} m

1 m=100 cm

We have to find the wavelength of laser light.

We know that

\Delta y=\frac{\lambda L}{d}

Substitute the values

1.56\times 10^{-2}=\frac{\lambda\times 4.75}{0.23\times 10^{-3}}

\lambda=\frac{1.56\times 10^{-2}\times 0.23\times 10^{-3}}{4.75}

\lambda=7.55\times 10^{-7} m

4 0
3 years ago
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