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hoa [83]
3 years ago
13

What is the relationship between Newton's first law of motion and inertia?​

Physics
1 answer:
adelina 88 [10]3 years ago
4 0

Explanation: Newton's first law of motion states that a body at rest remains at rest, or, if in motion, remains in motion at a constant velocity unless acted on by a net external force. This is also known as the law of inertia. Inertia is the tendency of an object to remain at rest or remain in motion.

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A student walks 3 north and 4 m west. The magnitude of the resultant displacement for the student is
evablogger [386]

Answer:

5m

Explanation:

Using Pythagoras theorem,

a^2+ b^2=c^2

3^2+4^2=c^2

25=c^2

√(25)=c

5m=c

6 0
3 years ago
What is the voltage in a circuit if the current is 6.2 A and the resistance is 18 ohms?
Nitella [24]
We already know the formula:
Voltage = Current * Resistance
In the given question, there are numerous information's that are already given.
Current = 6.2 A
Resistance = 18 ohms
Then
Voltage = 6.2 * 18 Volts
             = 111.6 Volt
So, the voltage in the circuit will be 111.6 volts. I hope it helps you.
4 0
4 years ago
Arrange the steps in order to describe what happens to a gas when it cools
QveST [7]

Answer:

when the gas cools it cools

Explanation:

6 0
3 years ago
A 65.0 kg skier slides down a 37.20 slope with mu = 0.107.<br><br>What is the friction force?
zmey [24]

Answer:

54.3N

Explanation:

The normal force is perpendicular to the slope, so:

Normal Force = cos(37.2)(9.8*65).......507.39N

F(friction)=mu*F(normal)

F(friction)=(0.107)(507.39)

F(friction)=54.3N

3 0
3 years ago
A bystander observes the musicians heading toward each other. When musician #1 is 100 m away, the intensity is 1.24 x 10-8 W/m^2
777dan777 [17]

Explanation:

Given that,

Distance 1, r = 100 m

Intensity, I_1=1.24\times 10^{-8}\ W/m^2

If distance 2, r' = 25 m

We need to find the intensity and the intensity level at 25 meters. Intensity and a distance r is given by :

I=\dfrac{P}{4\pi r^2}.........(1)

Let I' is the intensity at r'. So,

I'=\dfrac{P}{4\pi r'^2}............(2)

From equation (1) and (2) :

I'=\dfrac{Ir}{r'^2}

I'=\dfrac{1.24\times 10^{-8}\times 100}{25^2}

I'=1.98\times 10^{-9}\ W/m^2

Intensity level is given by :

dB=10\ log(\dfrac{I'}{I_o}), I_o=10^{-12}\ W/m^2

dB=10\ log(\dfrac{1.98\times 10^{-9}}{10^{-12}})

dB = 32.96 dB

Hence, this is the required solution.

7 0
3 years ago
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