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hoa [83]
3 years ago
13

What is the relationship between Newton's first law of motion and inertia?​

Physics
1 answer:
adelina 88 [10]3 years ago
4 0

Explanation: Newton's first law of motion states that a body at rest remains at rest, or, if in motion, remains in motion at a constant velocity unless acted on by a net external force. This is also known as the law of inertia. Inertia is the tendency of an object to remain at rest or remain in motion.

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If the dartboard below is used to model an atom, which subatomic particles would be located at Z? *
Anna11 [10]

I know that protons and neutrons are located at the center of an atom, so the correct answer is D

7 0
3 years ago
Which are examples of transverse waves? Check all that apply. earthquake P-waves earthquake S-waves radio waves sound visible li
Mariulka [41]
Earthquake S - Waves are examples of transverse waves. The correct option among all the options that are given in the question is the second option. Other good examples of transverse waves are an oscillating string and light waves. A wave is a kind of disturbance that or an oscillation that travels through space.
8 0
3 years ago
Read 2 more answers
A child’s toy that is made to shoot ping pong balls consists of a tube, a spring (k = 18 N/m) and a catch for the spring that ca
UkoKoshka [18]

Answer:

The height is 3.1m

Explanation:

Here we have a conservation of energy problem, we have a conversion form eslastic potencial  energy to gravitational potencial energy, so:

E_e=\frac{1}{2}K*x^2\\E_e=\frac{1}{2}18N/m*(9.5*10^{-2}m)^2\\E_e=0.081J

then we have only gravitational potencial energy when the ball is at its maximun height.

E_g=m*g*h

because all the energy was transformed Eg=Ee

h=\frac{0.081J}{9.8m/s^2*m}

searching the web, the mass of a ping pong ball is 2.7 gr in average. so:

h=\frac{0.081J}{9.8m/s^2*(2.7*10^{-3}kg)}\\h=3.1m

6 0
3 years ago
Suppose that you are standing on a train accelerating at 0.20g. What minimum coefficient of static friction must exist between y
Ilia_Sergeevich [38]
Acceleration = (0.2 x g) = 1.96m/sec^2. 
<span>Accelerating force on 1kg. = (ma) = 1.96N. </span>
<span>1kg. has a weight (normal force) of 9.8N. </span>
<span>Coefficient µ = 1.96/9.8 = 0.2 minimum. </span>

<span>Coefficient is a ratio, so holds true for any value of mass to find accelerating force acting. </span>
<span>e.g. 75kg = (75 x g) = 735N. </span>
<span>Accelerating force = (735 x 0.2) = 147N</span>
5 0
4 years ago
Read 2 more answers
A jet ski accelerates towards a ramp at 2.5 m/s/s for 35 s until it finally flies off the water. Determine the
zlopas [31]

Answer:

1531 m

Explanation:

The motion of the jet ski is an uniformly accelerated motion, so we can find the distance travelled by using the following suvat equation:

s=ut+\frac{1}{2}at^2

where

s is the distance

u is the initial velocity

t is the time

a is the acceleration

For the jet ski in this problem,

a=2.5 m/s^2

t = 35 s

u = 0 (it starts from rest)

Solving for s, we find the distance travelled:

d=0+\frac{1}{2}(2.5)(35)^2=1531 m

8 0
3 years ago
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