It is determined that a certain wave of infrared light has a wavelength of 8.45 mm. Given that c=2.99 ×108 m/s, what is the freq
2 answers:
Answer:
The frequency of infrared wave is 35.385 GHz
Explanation:
Given data:
Wavelength of infrared light = 8.45 mm = 8.45 x m
Velocity of infrared light = 2.99 x m/s
To find: frequency of the infrared wave = ?
We know that the wavelength and frequency are inversely proportional and the formula to derive frequency with velocity and wavelength is:
c = μλ, where
c is velocity of light
μ is frequency of light
λ is wavelength of light
Hence the frequency of light μ = c/λ
=
= x
= 35.385 x Hz (since 1
= 1 Hz)
= 35.385 GHz
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Answer:
This was my best estimation of the answers
Answer:
The correct answer is B
Explanation:
Let's calculate the electric field using Gauss's law, which states that the electric field flow is equal to the charge faced by the dielectric permittivity
Φ = ∫ E. dA =
/ ε₀
For this case we create a Gaussian surface that is a sphere. We can see that the two of the sphere and the field lines from the spherical shell grant in the direction whereby the scalar product is reduced to the ordinary product
∫ E dA = / ε₀
The area of a sphere is
A = 4π r²
E 4π r² = / ε₀
E = (1 /4πε₀ ) q / r²
Having the solution of the problem let's analyze the points:
A ) r = 3R / 4 = 0.75 R.
In this case there is no charge inside the Gaussian surface therefore the electric field is zero
E = 0
B) r = 5R / 4 = 1.25R
In this case the entire charge is inside the Gaussian surface, the field is
E = (1 /4πε₀ ) Q / (1.25R)²
E = (1 /4πε₀ ) Q / R2 1 / 1.56²
E₀ = (1 /4π ε₀ ) Q / R²
= Eo /1.56
²
= 0.41 Eo
C) r = 2R
All charge inside is inside the Gaussian surface
=(1 /4π ε₀
) Q 1/(2R)²
= (1 /4π ε₀
) q/R² 1/4
= Eo 1/4
= 0.25 Eo
D) False the field changes with distance
The correct answer is B