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jeka57 [31]
3 years ago
13

A pipe of length 6.8 m is closed at one end and sustains a standing wave at its second overtone. determine the distance between

a node and an adjacent antinode.

Physics
1 answer:
r-ruslan [8.4K]3 years ago
8 0
For a pipe closed at one end, the second overtone is the 3rd natural frequency as shown in the diagram.

For the fundamental frequency,
λ = 4L
where
λ = wavelength
L = the length of the tube

For the second overtone (3rd frequency)
λ = (4/3)L

Because L = 6.8 m, therefore
λ = (4/3)*(6.8 m) = 9.0667 m

The distance between a node and an adjacent antinode is λ/2, which is
9.0667/2 = 4.533 m

Answer: 4.5 m

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