There are
two things that you should remember while dealing with the "Lever Mechanical Advantage" problems:
1) The Effort Arm;
2) The Resistance Arm.
Some books label the Effort Arm as in-lever arm and the Resistance Arm as out-lever arm. (Physics Jargon that you need to remember in order to solve problems)
The Effort Arm is that "part" of the lever where the force can be applied. The Resistance Arm is where some mass is placed. In the diagram, as you can see, the mass is placed on one arm of the lever. Therefore, it is the Resistance Arm.
Now the formula for the "Mechanical Advantage(MA)" is:

Where

is the length of the Effort Arm(the subscript "e" stands for Effort), and

stands for the length of the Resistance Arm(here "r" stands for Resistance).
Plug in the values:

= 15m.

= 7m.
Therefore,

/

= 15/7 =
2.143 = MAThe correct answer is
option C(2.14).
-i
I believe it’s (D. Any object)
Explanation:
First, find the velocity of the projectile needed to reach a height h when fired straight up.
Given:
Δy = h
v = 0
a = -g
Find: v₀
v² = v₀² + 2aΔy
(0)² = v₀² + 2(-g)(h)
v₀ = √(2gh)
Now find the height reached if the projectile is launched at a 45° angle.
Given:
v₀ = √(2gh) sin 45° = √(2gh) / √2 = √(gh)
v = 0
a = -g
Find: Δy
v² = v₀² + 2aΔy
(0)² = √(gh)² + 2(-g)Δy
2gΔy = gh
Δy = h/2
Answer:
The ball has kinetic energy
the kinetic energy is 945 J
Explanation:
Answer:
<em>B) 1.0 × 10^5 V</em>
Explanation:
<u>Electric Potential Due To Point Charges
</u>
The electric potential produced from a point charge Q at a distance r from the charge is

The total electric potential for a system of point charges is equal to the sum of their individual potentials. This is a scalar sum, so direction is not relevant.
We must compute the total electric potential in the center of the square. We need to know the distance from all the corners to the center. The diagonal of the square is

where a is the length of the side.
The distance from any corner to the center is half the diagonal, thus


The total potential is

Where V1 and V2 are produced by the +4\mu C charges and V3 and V4 are produced by the two opposite charges of
. Since all the distances are equal, and the charges producing V3 and V4 are opposite, V3 and V4 cancel each other. We only need to compute V1 or V2, since they are equal, but they won't cancel.


The total potential is

