1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Agata [3.3K]
4 years ago
13

From the edge of a roof you throw a snowball downward that strikes the ground with 100J of kinetic energy. then you throw a seco

nd snowball upward with the same initial speed, and this too falls to the ground. neglecting air resistance, the second snowball hits the ground with a kinetic energy of:
a. 100J
b. 200J
c. more than 200J
d. less than 200J
e. none of the above
Physics
1 answer:
Vanyuwa [196]4 years ago
7 0

Answer:

The second snowball hits the ground with a kinetic energy of 100 Joules

Explanation:

Given that,

From the edge of a roof you throw a snowball downward that strikes the ground with 100 J of kinetic energy. It is a case of conservation of energy.

At the highest point,

mgh+\dfrac{1}{2}mu^2=mgh'+0          

100=mgh'

At lowest point,

mgh'=K

From above two equation, we get :

Kinetic energy, K = 100 J

So, the second snowball hits the ground with a kinetic energy of 100 Joules. So, the correct option is (A).                                                                        

You might be interested in
Determine the MA based on the diagram below.
artcher [175]
There are two things that you should remember while dealing with the "Lever Mechanical Advantage" problems:

1) The Effort Arm;
2) The Resistance Arm.

Some books label the Effort Arm as in-lever arm and the Resistance Arm as out-lever arm. (Physics Jargon that you need to remember in order to solve problems)

The Effort Arm is that "part" of the lever where the force can be applied. The Resistance Arm is where some mass is placed. In the diagram, as you can see, the mass is placed on one arm of the lever. Therefore, it is the Resistance Arm.

Now the formula for the "Mechanical Advantage(MA)" is:
MA =  \frac{L_{e} }{ L_{r} }

Where L_{e} is the length of the Effort Arm(the subscript "e" stands for Effort), and L_{r} stands for the length of the Resistance Arm(here "r" stands for Resistance).

Plug in the values:

L_{e} = 15m.
L_{r} = 7m.

Therefore, L_{e} / L_{r} = 15/7 = 2.143 = MA

The correct answer is option C(2.14).

-i

3 0
3 years ago
Read 2 more answers
Gravity does not actually "pull" objects at
Radda [10]
I believe it’s (D. Any object)
5 0
3 years ago
How do you do this problem?
kvasek [131]

Explanation:

First, find the velocity of the projectile needed to reach a height h when fired straight up.

Given:

Δy = h

v = 0

a = -g

Find: v₀

v² = v₀² + 2aΔy

(0)² = v₀² + 2(-g)(h)

v₀ = √(2gh)

Now find the height reached if the projectile is launched at a 45° angle.

Given:

v₀ = √(2gh) sin 45° = √(2gh) / √2 = √(gh)

v = 0

a = -g

Find: Δy

v² = v₀² + 2aΔy

(0)² = √(gh)² + 2(-g)Δy

2gΔy = gh

Δy = h/2

5 0
3 years ago
You serve a volleyball with a mass of 2.1 kg. The ball leaves your hand with a speed of 35 m/s. The ball has __________________
Elden [556K]

Answer:

The ball has kinetic energy

the kinetic energy is 945 J

Explanation:

4 0
3 years ago
Read 2 more answers
A square is 1.0 m on a side. Point charges of +4.0 μC are placed in two diagonally opposite corners. In the other two corners ar
finlep [7]

Answer:

<em>B) 1.0 × 10^5 V</em>

Explanation:

<u>Electric Potential Due To Point Charges </u>

The electric potential produced from a point charge Q at a distance r from the charge is

\displaystyle V=k\frac{Q}{r}

The total electric potential for a system of point charges is equal to the sum of their individual potentials. This is a scalar sum, so direction is not relevant.

We must compute the total electric potential in the center of the square. We need to know the distance from all the corners to the center. The diagonal of the square is

d=\sqrt2 a

where a is the length of the side.

The distance from any corner to the center is half the diagonal, thus

\displaystyle r=\frac{d}{2}=\frac{a}{\sqrt{2}}

\displaystyle r=\frac{1}{\sqrt{2}}=0.707\ m

The total potential is  

V_t=V_1+V_2+V_3+V_4

Where V1 and V2 are produced by the +4\mu C charges and V3 and V4 are produced by the two opposite charges of \pm 3\mu\ C. Since all the distances are equal, and the charges producing V3 and V4 are opposite, V3 and V4 cancel each other. We only need to compute V1 or V2, since they are equal, but they won't cancel.

\displaystyle V_1=V_2=k\frac{Q}{r}=9\times 10^9 \frac{4\times 10^{-6}}{0.707}

V_1=V_2=50912\ V

The total potential is

V_t=50912\ V+50912\ V=1\times 10^5\ V

\boxed{V_t=1\times 10^5\ V}

6 0
3 years ago
Other questions:
  • Pirates drag a treasure chest to the left across a sandy beach. In which direction does the treasure chest experience a friction
    8·1 answer
  • Kate is working on a project in her tech education class. She plans to assemble a fan motor. Which form of energy does the motor
    12·1 answer
  • Formula One racers speed up much more quickly than normal passenger vehicles, and they also can stop in a much shorter distance.
    10·1 answer
  • initially, a particle is moving at 5.33 m/s at an angle of 37.9° above the horizontal. Two seconds later, its velocity is 6.11 m
    7·1 answer
  • HELPPPP!!!!!
    6·2 answers
  • If displacement per unit time is tripled, the velocity is by a factor of .
    8·1 answer
  • An airplane used to drop water on brushfires is flying horizontally in a straight line at 180 mi/h at an altitude of 390 ft. Det
    8·1 answer
  • Water will expand more than ___<br><br> A. door<br> B. juice<br> C. air
    11·2 answers
  • Nerf this hbhbhbbhbbhbhbhbhbhbhb
    11·2 answers
  • What must be known to determine the direction of the magnetic force on a change? Check all that apply.
    11·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!