Explanation:
It is given that, a long, straight wire is surrounded by a hollow metal cylinder whose axis coincides with that of the wire.
The charge per unit length of the wire is 
and the net charge per unit length is 
.
We know that there exist zero electric field inside the metal cylinder.
(a) Using Gauss's law to find the charge per unit length on the inner and outer surfaces of the cylinder. Let 
are the charge per unit length on the inner and outer surfaces of the cylinder.
For inner surface,
For outer surface,
(b) Let E is the electric field outside the cylinder, a distance r from the axis. It is given by :
Hence, this is the required solution.
Answer:
Explanation:
As the path is straight, so the speed is equivalent to velocity. Now. assuming that the acceleration and deceleration of the train are constant. So, change of velocity with respect to time for acceleration as well as deceleration is constant. Hence, the slope of the speed-time graph is constant for the time of acceleration as well as deceleration. The speed for the time from 
to 
is constant, so slope for this interval of time is zero. The speed-time graph is shown in the figure.
The total distance covered by the train during the entire journey is the area of the speed-time graph.
Area
As velocity is in 
and time is in 
so the unit of area is 
Hence, the total distance is 
.
Answer:
<h2>15.25 N</h2>
Explanation:
A force of 
is acting on a wagon along the road. The wagon weights 
. Acceleration of the wagon is given as 
.
Consider the block as the system, the forces acting are Frictional force, Gravitational force, Normal reaction and External force applied by us.
Gravitational Force and Normal Reaction cancel out each other.
Net External Force = Mass of system/wagon 
Acceleration of wagon
has a negative sign because it opposes the motion of the wagon.
∴ Frictional Force = 15.25 N
1.c
2.b
3.a
4.c
5.b
I hop this helps
Explanation:
A centripetal force (from Latin centrum, "center" and petere, "to seek") is a force that makes a body follow a curved path. (not sure but hope this helps )
