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Anestetic [448]
3 years ago
8

The index of refraction for flint glass is 1.5. This means that

Physics
2 answers:
Alexxx [7]3 years ago
7 0

Answer:

Explanation:

This means that the ratio of the speed of the incident beam of light in a vacuum to the speed of light in the glass is 1.5

Harlamova29_29 [7]3 years ago
5 0

This means that the speed of light in vacuum is 1.5 times the speed of light in flint glass.

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An unknown galaxy has a large flattened core. Which of the following classifications would best fit this galaxy's description? I
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Spiral

i know it is so dont say nun people

Explanation:

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3) A 900N mountain climber scales a 100m cliff. How much work is done by the mountain climber?
Y_Kistochka [10]

Answer:

90 kJ

Explanation:

Work = force × distance

W = (900 N) (100 m)

W = 90,000 J

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The atoms in a solid move about freely
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Two astronauts are taking a spacewalk outside the International Space
Tems11 [23]

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3 years ago
A tank is full of water. Find the work W required to pump the water out of the spout. (Use 9.8 m/s2 for g. Use 1000 kg/m3 as the
Sergio039 [100]

Answer:

W = 1.06 MJ

Explanation:

- We will use differential calculus to solve this problem.

- Make a differential volume of water in the tank with thickness dx. We see as we traverse up or down the differential volume of water the side length is always constant, hence, its always 8.

- As for the width of the part w we see that it varies as we move up and down the differential element. We will draw a rectangle whose base axis is x and vertical axis is y. we will find the equation of the slant line that comes out to be y = 0.5*x. And the width spans towards both of the sides its going to be 2*y = x.

- Now develop and expression of Force required:

                                             F = p*V*g

                                             F = 1000*(2*0.5*x*8*dx)*g

                                             F = 78480*x*dx

- Now, the work done is given by:

                                             W = F.s

- Where, s is the distance from top of hose to the differential volume:

                                             s = (5 - x)

- We have the work as follows:

                                            dW = 78400*x*(5-x)dx

- Now integrate the following express from 0 to 3 till the tank is empty:

                                           W = 78400*(2.5*x^2 - (1/3)*x^3)

                                           W = 78400*(2.5*3^2 - (1/3)*3^3)

                                           W = 78400*13.5 = 1058400 J

 

5 0
3 years ago
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