My answer is....A
sorry if im wrong
The reaction is
FeO + Fe3O4 + 1/2 O2---> 2Fe2O3
Thus as shown in the balanced equation two moles of Fe2O3 are formed when 0.5 moles of O2 reacted with mixture of FeO and Fe3O4
moles of Fe2O3 = MAss / Molar mass = 4.141 / 159.69 = 0.0259 moles
So moles of O2 needed = 0.5 X 0.0259 = 0.01295
Mass of O2 = moles X molar mass = 0.01295 X 32 = 0.4144 grams
Answer:
2 sig figs.
Explanation:
Sig Fig Rules:
Any non-zero digit is a significant figure.
Any zeros between 2 non-zero digits are significant figures.
Trailing zeros after the decimal are significant figures.
Answer:
The final temperature of the water will be 328.81 K .
Explanation:
Using the equation, <em>q = mcΔT</em>
here, <em>q = energy</em>
<em>m= mass</em>
<em>c= specific heat capacity </em>
<em>ΔT= change in temperature</em>
<em>Mass of water = 1kg (1000 g ) per liter</em>
<em>∴ 6.2 Liter of water = 6200 g</em>
<em>c of water ≈ 4.18 J /g/K</em>
<em>Now, </em>
<em>980000 = 6200*4.18*ΔT</em>
<em>ΔT = 37.81 K</em>
<em>∴ final temperature of the water = 291 + 37.81 = 328.81 K</em>
