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raketka [301]
3 years ago
13

What is 4x+ 9y +3 (x+y) simplified?

Mathematics
1 answer:
RoseWind [281]3 years ago
8 0

Answer:

7x+12y

Step-by-step explanation:

Simplify

4x+9y+3(x+y)

<em>Use the distributive property to multiply 3 by x+y. </em>

4x+9y+3x+3y

<em>Combine 4x and 3x to get 7x. </em>

7x+9y+3y

<em>Combine 9y and 3y to get 12y. </em>

7x+12y

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Step-by-step explanation:

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The number of chocolate chips in a bag of chocolate chip cookies is approximately normally distributed with a mean of 1262 chips
Sholpan [36]

Answer:

Using z score formula:

X = z ∂ + µ

 = 157.833

Step-by-step explanation:

Solution:

Mean = µ = 1262

Standard deviation = ∂ = 117

(a) 28th percentile for the number of chocolate chip.

P( z < z) = 28%

             = 0.28

P( z<- 0.58)  = 0.28

Z = -0.58

By using z score formula:

Z = x - µ /∂

-0.58= x – 117 / 1262

X = (- 0.58)(117) + (1262)

 =  1194.14

(b) Middle 97% of bag.

P(-z < z < z) = 97%

                    = 0.97

P( z < z) – p(z < -z) = 0.97

2p(z < z) -1 = 0.97

2p (z < z) = 1 + 0.97

P(z < z) = 1.97 / 2

            = 0.99

P(z < 2.33) = 0.99

Z ± 2.33

By using z score formula:

Z = x - µ / ∂

X = z ∂ + µ

  = - 2.33 x 117 + 1262

  =989.39

Z = 2.33

X = z ∂ + µ

  =  2.33 x 117 + 1262

 =1533.61

(c) What is the interquartile range of the number of chocolate chips in a bag of chocolate.

By using standard normal table,

The z dist’n formula:

P(z < z ) = 25%

            =0.25

P(z < -0.6745) = 0.25

Z = 0.6745

Using z score formula:

X = z∂ + µ

   = - 0.6745 x 117 + 1262

  = 1183.0835

First quartile = Q1 =1183.0835

The third quartile is:

P(z<z) = 75%

    = 0.75

P(z < 0.6745) = 0.75

Z = 0.6745

Using z score formula:

X = z ∂ + µ

  = 0.6745 x 117 + 1262

= 1340.9165

IQR = Q3 – Q1

     = 1340.9165 – 1183.0835

  = 157.833

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Step-by-step explanation:

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Step-by-step explanation:

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What is the area of the trapezoid? Leave the answer in simplest radical form. The figure is not drawn to scale.
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Answer:

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Step-by-step explanation:

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The vertical side length of the triangle is the same, because the triangle is an isosceles right triangle.

Since we know the base lengths and height of the trapezoid, we can use the usual formula for the area:

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