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mash [69]
3 years ago
7

(25 Points) Choose acid, base, or neutral.

Chemistry
1 answer:
MaRussiya [10]3 years ago
6 0

Answer:

Hydrogen ions are spontaneously generated in pure water by the dissociation (ionization) of a small percentage of water molecules into equal numbers of hydrogen (H+) ions and hydroxide (OH–) ions. The hydroxide ions remain in solution because of their hydrogen bonds with other water molecules; the hydrogen ions, consisting of naked protons, are immediately attracted to un-ionized water molecules and form hydronium ions (H30+). By convention, scientists refer to hydrogen ions and their concentration as if they were free in this state in liquid water.

2

H

2

O

⇋

H

3

O

+

+

OH

−

2H2O⇋H3O++OH−

The concentration of hydrogen ions dissociating from pure water is 1 × 10-7 moles H+ ions per liter of water. The pH is calculated as the negative of the base 10 logarithm of this concentration:

pH

=

−

l

o

g

[

H

+

]

pH=−log[H+]

The negative log of 1 × 10-7 is equal to 7.0, which is also known as neutral pH. Human cells and blood each maintain near-neutral pH.

pH Scale

The pH of a solution indicates its acidity or basicity (alkalinity). The pH scale is an inverse logarithm that ranges from 0 to 14: anything below 7.0 (ranging from 0.0 to 6.9) is acidic, and anything above 7.0 (from 7.1 to 14.0) is basic (or alkaline ). Extremes in pH in either direction from 7.0 are usually considered inhospitable to life. The pH in cells (6.8) and the blood (7.4) are both very close to neutral, whereas the environment in the stomach is highly acidic, with a pH of 1 to 2.

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The following reaction has been reported in the chemical literature and gives a single organic product in high yield. Write the
Alla [95]

Answer:

Explanation:

The principle applied is the Markovnikoff's rule which states that when hydrogen chloride adds to a double bond, the hydrogen atoms join to the carbon that already has the most hydrogen atoms bonded to it. The rule wa postulated by a russian chemist known as Vladimir Markovnikoff.

In the markovnikoff's rule, there are sveral conditions that must be met, one of them is that no free radicals must be involved.

The reaction and the structure of the product is as shown in the attachment.

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3 years ago
Which organelle this illustration represent?
Tema [17]
That illustration represents the mitochondria 
5 0
3 years ago
A solution of NaOH is titrated with H2SO4. It is found that 20.05 mL of 0.3564 M H2SO4 solution is equivalent to 43.42 mL of NaO
Darya [45]

Answer : The concentration of NaOH is, 0.336 M

Explanation:

To calculate the concentration of base, we use the equation given by neutralization reaction:

n_1M_1V_1=n_2M_2V_2

where,

n_1,M_1\text{ and }V_1 are the n-factor, molarity and volume of acid which is H_2SO_4

n_2,M_2\text{ and }V_2 are the n-factor, molarity and volume of base which is NaOH.

We are given:

n_1=2\\M_1=0.3564M\\V_1=20.05mL\\n_2=1\\M_2=?\\V_2=43.42mL

Putting values in above equation, we get:

2\times 0.3564M\times 20.05mL=1\times M_2\times 43.42mL

M_2=0.336M

Thus, the concentration of NaOH is, 0.336 M

3 0
3 years ago
What is formula mass of glucose C2H12O6
Delvig [45]
Glucose has empirical formula C6H12O6. So its formula mass can be calculated from that: 12.01x6 + 1.008x12 + 16.00x6 = 72.06 + 12.096 + 96.00 = 180.156 which needs to be rounded to two decimals to get 180.16 g/mole<span>.</span>
3 0
4 years ago
Phosphorus pentachloride decomposes according to this equation. PCl5(g) equilibrium reaction arrow PCl3(g) + Cl2(g) An equilibri
melisa1 [442]

Answer:

PCl₅ = 0.03 X 208 = 6.24g

PCl₃ = 0.05 X 137 =6.85 g

Cl₂ = 0.03X71 = 2.13 g

Explanation:

The equilibrium constant will remain the same irrespective of the amount of reactant taken.

Let us calculate the equilibrium constant of the reaction.

Kc=\frac{[PCl_{3}][Cl_{2}]}{[PCl_{5}]}

Let us calculate the moles of each present at equilibrium

moles=\frac{mass}{molarmass}

molar mass of PCl₅=208

molar mass of PCl₃=137

molar mass of Cl₂=71

moles of PCl₅ = \frac{mass}{molarmass}=\frac{4.13}{208}=0.02

moles of PCl₃= \frac{mass}{molarmass}=\frac{8.87}{137}=0.06

moles of Cl₂ = \frac{mass}{molarmass}=\frac{2.90}{71}=0.04

the volume is 5 L

So concentration will be moles per unit volume

Putting values

Kc = \frac{\frac{0.06}{5}\frac{0.04}{5}}{\frac{0.02}{5}}=0.024

Now if the same moles are being transferred in another beaker of volume 2L then there will change in the concentration of each as follow

                PCl_{5}--->PCl_{3}+Cl_{2}

Initial                 0.02           0.06       0.04

Change             -x                   +x          +x

Equilibrium     0.02-x           0.06+x    0.04+x

Conc.                (0.02-x)/2       (0.06+x)/2   (0.04+x)/2

Putting values

0.024 = \frac{(0.06+x)(0.04+x)}{(0.02-x)2}

Solving

(0.024(2)(0.02-x)=(0.06+x)(0.04+x)

0.00096-0.048x=0.0024+x^{2}+0.1x

0.148x+x^{2}+0.00144=0

x = -0.01

so the new moles of

PCl₅ = 0.02 + 0.01  =0.03

PCl₃ = 0.06-0.01 = 0.05

Cl₂ = 0.04-0.01 = 0.03

mass of each will be:

mass= moles X molar mass

PCl₅ = 0.03 X 208 = 6.24g

PCl₃ = 0.05 X 137 =6.85 g

Cl₂ = 0.03X71 = 2.13 g

5 0
4 years ago
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