69.9%
Explanation:
To find the mass percentage of iron in the compound in Fe₂O₃, we would go ahead to express the given molar mass of the iron to that of the compound.
Mass percentage = x 100
Molar mass of Fe = 55.85g/mol
Molar mass of O = 16g/mol
Molar mass of Fe₂O₃ = 2(55.85) + 3(16) = 159.7g/mol
Mass percentage = = 69.94% = 69.9%
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Mass percentage brainly.com/question/8170905
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Answer:
Explanation:
From the question, we have been asked to find the molarity of FeCl2 having a volume of 450 mL,
We have been provided with 225 g which is proportional to 1.8 moles.
We know that molarity of any solution should be in mol/L.
1 mole contained in 1 L means it has a molarity of 1 mol/L
Let's convert 450 mL to Litres which is,
= 0.450 L
Thus,
1 mole is contained in 1L
x moles are contained in 0.450 L
Hence,
x mole/molarity = {1 mole x 1 L}/{0.450 L}
= 4 mol/L
Therefore 4 mol/L is the molar concentration.
Answer:
Hope this helps!
Explanation:
I would help you, but I won't. Because you take others people points without helping them and but random words. So, since you are doing that I won't be helping you <3. Thanks for the points idiot.
