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IRISSAK [1]
3 years ago
15

The Lanthanides are often be found below the Periodic Table so it will fit nicely on a textbook page. If they were inserted into

the Periodic Table, where would they go?
group 7
group 6
period 7
period 6
Chemistry
1 answer:
Annette [7]3 years ago
6 0

Answer:

period 6

Explanation:

If the lanthanides were inserted into the periodic table, they would go into periodic 6.

Their atomic number is between 57 - 71 from element lanthanum to lutetium.

  • The elements in this period are 15 in number.
  • They are also know as elements in the f-block.

The elements that makes up the series are:

Lanthanum

Cerium

Praseodymium

Neodymium

Promethium

Samarium

Europium

Gadolinium

Terbium

Dysprosium

Holmium

Erbium

Thulium

Ytterbium

Lutetium

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omeli [17]

Answer:

8/3 hours

Explanation:

12.5/100=1/8, 1/8*2=2/8=1/4 1/4*2=1/2 1/2*2 = 1 (whole)

we multiplyed 1/8 by two three times to get 1 so 8/3 hours is the answer

by the way i'm in 6th grade

3 0
3 years ago
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Alexxandr [17]

krill and plankton

false

true

sunlight

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Explanation:

6 0
3 years ago
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iren [92.7K]

Answer:

B

Explanation:

Noble gases are in group 18 (neon, argon, etc)

7 0
3 years ago
What is the minimum pressure in kPa that must be applied at 25 °C to obtain pure water by reverse osmosis from water that is 0.2
Nadya [2.5K]

This is an application of osmotic pressure which is one of the colligative properties of substances. The formula of osmotic pressure is expressed as P = MRT where M is molarity , R is the gas constant and T is temperature. When M is equal to a total of 0.305 M and T is equal to 298 K ,  P should be equal to 7.46 atm
3 0
3 years ago
A beaker contains 42.0 mL of carbon tetrachloride ( CCl4 , density is 1.59 g/mL). Determine how many molecules of carbon tetrach
Alex

Answer:

Number of molecules = 2.61  x 10²³

Explanation:

Given:

Volume of tetra-chloride = 42 ml

Density = 1.59 g/ml

Find:

Number of molecules

Computation:

Mass = Volume of tetra-chloride x Density

Mass = 42 x 1.59

Mass = 66.78

Molecular mass of tetra-chloride = 154 g/mol

Moles = 66.78 / 154

Moles = 0.4337

0.4337 mole = 0.4337 x Avogadro number

0.4337 mole = 0.4337 x 6.022 x 10²³

Number of molecules = 2.61  x 10²³

3 0
3 years ago
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