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IRISSAK [1]
3 years ago
15

The Lanthanides are often be found below the Periodic Table so it will fit nicely on a textbook page. If they were inserted into

the Periodic Table, where would they go?
group 7
group 6
period 7
period 6
Chemistry
1 answer:
Annette [7]3 years ago
6 0

Answer:

period 6

Explanation:

If the lanthanides were inserted into the periodic table, they would go into periodic 6.

Their atomic number is between 57 - 71 from element lanthanum to lutetium.

  • The elements in this period are 15 in number.
  • They are also know as elements in the f-block.

The elements that makes up the series are:

Lanthanum

Cerium

Praseodymium

Neodymium

Promethium

Samarium

Europium

Gadolinium

Terbium

Dysprosium

Holmium

Erbium

Thulium

Ytterbium

Lutetium

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How many moles are in 35.0 grams of H₂O?
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1.94 moles


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If a object has a mass of 10 kilograms, how much does it weigh in newtons?
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5 0
2 years ago
For the reaction 2 NO(g) + 2 H2(g) => N2(g) + 2 H2O(g) the following data were collected. What is the rate law for this react
harkovskaia [24]

<u>Answer:</u> The rate law expression for the given reaction is written below.

<u>Explanation:</u>

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5 0
3 years ago
A 0.1 mm sample of human blood has approximately 6000 red blood cells. An adult typically has 5.0 L of blood. How many red blood
olga55 [171]

 3.0 × 10¹¹ RBC's    (or)      3E11 RBC's


Solution:

Step 1: Convert mm³ into L;


As,


                                            1 mm³  =  1.0 × 10⁻⁶ Liters


So,


                                         0.1 mm³  =  X  Liters


Solving for X,


                       X  =  (0.1 mm³ × 1.0 × 10⁻⁶ Liters) ÷ 1 mm³


                       X  =  1.0 × 10⁻⁷ Liters


Step 2: Calculate No. of RBC's in 5 Liter Blood:


As given


                        1.0 × 10⁻⁷ Liters Blood contains  =  6000 RBC's


So,


                         5.0 Liters of Blood will contain  =  X  RBC's


Solving for X,


                      X  =  (5.0 Liters × 6000 RBC's) ÷ 1.0 × 10⁻⁷ Liters


                      X  =  3.0 × 10¹¹ RBC's


Or,


                     X  =  3E11 RBC's



5 0
3 years ago
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