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Eduardwww [97]
3 years ago
9

5. Rebecca bought candy boxes in the shape of a square pyramid to use for party favors. The side length of each box is 3.6 inche

s, and the height is 4 inches. Rebecca wants to fill each box with 20 pieces of candy. If each piece of candy is 0.8 in.³, will Rebecca be able to fit 20 pieces of candy into each candy box?
Mathematics
1 answer:
irina [24]3 years ago
3 0

Answer:17.28 and yes

Step-by-step explanation:because I did it in school and I don’t remember how to do it

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Identify the pair of supplementary angles.
777dan777 [17]

▪▪▪▪▪▪▪▪▪▪▪▪▪  {\huge\mathfrak{Answer}}▪▪▪▪▪▪▪▪▪▪▪▪▪▪

We know that, the sum of measures of supplementary angles is 180°

So, the Correct choice is :

  • 65° and 115°

because, 65° + 115° = 180°

7 0
3 years ago
Please help me with this! I’m so lost :((
frozen [14]

Answer:

# 1 reb #2 is cfs

hope i could help...........

6 0
3 years ago
Please explain your answer. Thank you!
Liula [17]

Answer:

C

Step-by-step explanation:

Let length of rectangle be "l"

Let width of rectangle be "w"

We know,

LENGTH is 2 MORE THAN WIDTH, we can write:

l = w + 2

Also, note the perimeter is the sum of all 4 sides of a rectangle, thus:

length + width + length + width

Now,

The perimeter is given as 72, so we can write:

l + l + w + w = 72

2l + 2w = 72

We have 2 equations that we need to solve and find the length (l).

The first equation is:

l = w + 2

Rearranging, we have:

w = l - 2

We put this into 2nd equation and find the value of l:

2l + 2w = 72\\2l + 2(l-2) = 72\\2l+2l-4=72\\4l-4=72\\4l=76\\l=\frac{76}{4}\\l=19

The length is 19 meters, the correct answer is C

3 0
4 years ago
If the length of a rectangle in terms of x is x^2+2x-3 and its width is 2x^2+3x+5, what is the perimeter of this rectangle?
AnnZ [28]

Step-by-step explanation:

perimeter=(L+W)2

L=x^2+2x-3

W=2x^2+3x+5

(x^2+2x-3+2x^2+3x+5)2

(x^2+2x^2+2x+3x-3+5)2

(3x^2+5x+2)2

p=(6x^2+10x+4)units

3 0
3 years ago
If x=5 and y=2<br> ...........................
azamat

{ \bold{ - 5}}

{ \red{ \tt{given \: {\to}}}} \: { \bold{x = 5}} \:  \\  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  { \bold{y = 2}}

{ \green{ \tt{ \sqrt{10y + x} - xy}}}

{ \green{ \tt{ \sqrt{10(2) + 5 }  - 5(2)}}}

{ \green{ \tt{ \sqrt{20 + 5}  - 10}}}

{ \green{ \tt{ \sqrt{25}  - 10}}}

{ \green{ \tt{5} - 10}}

=  { \bold{ - 5}}

8 0
1 year ago
Read 2 more answers
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