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3 years ago

What is the equation of the line that is perpendicular to

Mathematics

1 answer:

ziro4ka [17]3 years ago

8 0

Answer:

Step-by-step explanation:

The given line is parallel to X-axis, so its equation is y = b (b is its intersect of Y-axis)

Therefore the perpendicular line has to be parallel to Y-axis, so its equation will be x = x₀, where x₀ is its intersect of X-axis and x-coordinate of any point it passes through.

(2, 6) ⇒ x₀ = 2

so the equation is

x = 2

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I’m hella confused????

Alexeev081 [22]

Answer:

same but use photomath its good

8 0

3 years ago

Juli buys a flat with 48 flowers. She was wants to plant them in equal rows of 5 flowers. How many rows can Juli plant? How many

miss Akunina [59]

Answer:

5 row, 3 left

Step-by-step explanation:

She has 48 flowers, 5 flowers one row

How many rows can she make? So divide

48/ 5

= 9.6

So she can only make 9 rows

The leftovers flowers are the flowers that didn't manage to make 5 per row

Therefore, if she can make 9 rows, in other words 9 x 5 = 45

45 flowers were able to be placed in a sequence of 5 per row

So the ones that are left is

48 - 45

= 3

8 0

3 years ago

Find the quotient 1 5 ÷ 3 4 = _____

zavuch27 [327]

Answer:

15/34=0.44117647058823529411764705882353‬

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

Find all the zeros of the polynomial function p(x) = x3 – 5x2 + 33x – 29

hram777 [196]

Answer:

$\large \boxed{\sf \ \ x=1, \ \ x=2+5i, \ \ x=2-5i \ \ }$

Step-by-step explanation:

Hello,

I assume that we are working in $\mathbb{C}$ , otherwise there is only one zero which is 1. Please consider the following.

First of all, <u>we can notice that 1 is a trivial solution</u> as

$p(1) = 1^3-5\cdot 1^2 + 33\cdot 1-29=1-5+33-29=0$

It means that (x-1) is a factor of p(x) so we can find two real numbers, a and b, so that we can write the following.

$p(x)=(x-1)(x^2+ax+b)=x^3+ax^2+bx-x^2-ax-b=x^3+(a-1)x^2+(b-a)x-b$

Let's identify like terms as below.

a-1 = -5 <=> a = -5 + 1 = -4

b-a = 33

-b = -29 <=> b = 29

$\boxed{ \ p(x)=(x-1)(x^2-4x+29) \ }$

Now, we need to find the zeroes of the second factor, meaning finding x so that:

$x^2-4x+29=0 \ \text{ complete the square, 29 = 25 + 4} \\ \\ x^2-2\cdot 2 \cdot x+2^2+25=0 \\ \\ (x-2)^2=-25=(5i)^2 \ \text{ take the root } \\ \\x-2=\pm 5i \ \text{ add 2 } \\ \\ x = 2+5i \ \text{ or } \ x = 2-5i$

Hope this helps.

Do not hesitate if you need further explanation.

Thank you

5 0

3 years ago

tim brought a car 25000 and it depreciation $350 per year. What is the value of the car after 6 years?

blondinia [14]

Answer:

22900

Step-by-step explanation:

multiply 350 by 6 and get 2100

subtract 2100 from 25k and get 22900

6 0

4 years ago

Read 2 more answers