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Over [174]
2 years ago
10

Help me please. This is my last question

Mathematics
1 answer:
Crazy boy [7]2 years ago
3 0

Answer: D. 44

Step-by-step explanation:

Here, we need to know the concept of trigonometry.

  • Sine (sin) = Opposite/Hypotenuse = O/H
  • Cosine (cos) = Adjacent/Hypotenuse = A/H
  • Tangent (tan) = Oppostie/Adjacent = O/A

-----------------------------------------------------------------------------

Given

- The adjacent side of angle x and the hypotenuse.

- We are going to use Cosine.

<u>Solve</u>

cos (x) = 15/21

       x  = cos⁻¹ (15/21)

       x  ≈ 44

Hope this helps!! :)

Please let me know if you have any questions

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muminat

Answer:

t= - 48

Step-by-step explanation:

t/8 - 6= -12 add 6 to both side

t/8= -6 multiple by 8

t= -48

3 0
3 years ago
Read 2 more answers
4(h+11)-15<br> The solution
skad [1K]

Answer:

=4h+29

Step-by-step explanation:

I hope this helps you

7 0
3 years ago
∠1 and ∠2 are a linear pair. m∠1 = x - 29, and m∠2 = x + 61. Find the measure of each angle.
Oduvanchick [21]

<em>So</em><em>,</em>

<em>m</em><em><</em><em>1</em><em>=</em><em>4</em><em>5</em><em>,</em><em> </em><em>m</em><em><</em><em>2</em><em>=</em><em>1</em><em>3</em><em>5</em>

<em>So</em><em> </em><em>t</em><em>he</em><em> </em><em>right</em><em> </em><em>answer</em><em> </em><em>is</em><em> </em><em>of</em><em> </em><em>option</em><em> </em><em>D</em><em>.</em>

<em>Look</em><em> </em><em>at</em><em> </em><em>the</em><em> </em><em>attached</em><em> </em><em>picture</em>

<em>H</em><em>ope</em><em> </em><em>it</em><em> </em><em>will</em><em> </em><em>help</em><em> </em><em>you</em>

<em>Good</em><em> </em><em>luck</em><em> </em><em>on</em><em> </em><em>your</em><em> </em><em>assignment</em>

3 0
3 years ago
1 pts
lubasha [3.4K]

Answer: I believe the answer to your question is 4

Step-by-step explanation:

8 0
3 years ago
Please help me I have been stuck on this question for ages
Finger [1]

Answer:28 green and 35 red

Step-by-step explanation:

Given

If there are r red counter and g green counter then

Probability of drawing a green counter is P(g)=\frac{4}{9}

and P(g)=\frac{\text{No of g counter}}{\text{Total no of counter}}

Thus \frac{\text{No of g counter}}{\text{Total no of counter}}=\frac{4}{9}

\frac{g}{g+r}=\frac{4}{9}

\Rightarrow 9g=4g+4r

\Rightarrow 5g=4r\quad \ldots(i)

Also if 4 red and 2 green counter is added the probability of drawing a green counter is

P(g)=\frac{10}{23}=\frac{\text{No of g counter}}{\text{Total no of counter}}

\Rightarrow \frac{10}{23}=\frac{g+2}{g+2+r+4}

\Rightarrow \frac{10}{23}=\frac{g+2}{g+r+6}

\Rightarrow 10g+10r+60=23g+46

\Rightarrow 10r+14=13g\ quad \ldots(ii)

Substitute the value of g in equation (ii)[/tex]

\Rightarrow 10\times \frac{5}{4}g+14=13g

\Rightarrow \frac{25}{2}g+14=13g

\Rightarrow g=28

Therefore r=35

Thus there 28 green counter and 35 red counter

6 0
3 years ago
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