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2 years ago

Help me please. This is my last question

Mathematics

1 answer:

Crazy boy [7]2 years ago

3 0

Answer: D. 44

Step-by-step explanation:

Here, we need to know the concept of trigonometry.

Sine (sin) = Opposite/Hypotenuse = O/H
Cosine (cos) = Adjacent/Hypotenuse = A/H
Tangent (tan) = Oppostie/Adjacent = O/A

-----------------------------------------------------------------------------

Given

- The adjacent side of angle x and the hypotenuse.

- We are going to use Cosine.

Solve

cos (x) = 15/21

x = cos⁻¹ (15/21)

x ≈ 44

Hope this helps!! :)

Please let me know if you have any questions

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Help help help help help help

muminat

Answer:

t= - 48

Step-by-step explanation:

t/8 - 6= -12 add 6 to both side

t/8= -6 multiple by 8

t= -48

3 0

3 years ago

Read 2 more answers

4(h+11)-15 The solution

skad [1K]

Answer:

=4h+29

Step-by-step explanation:

I hope this helps you

7 0

3 years ago

∠1 and ∠2 are a linear pair. m∠1 = x - 29, and m∠2 = x + 61. Find the measure of each angle.

Oduvanchick [21]

So,

m<1=45, m<2=135

So the right answer is of option D.

Look at the attached picture

Hope it will help you

Good luck on your assignment

3 0

3 years ago

1 pts

lubasha [3.4K]

Answer: I believe the answer to your question is 4

Step-by-step explanation:

8 0

3 years ago

Please help me I have been stuck on this question for ages

Finger [1]

Answer:28 green and 35 red

Step-by-step explanation:

Given

If there are r red counter and g green counter then

Probability of drawing a green counter is $P(g)=\frac{4}{9}$

and $P(g)=\frac{\text{No of g counter}}{\text{Total no of counter}}$

Thus $\frac{\text{No of g counter}}{\text{Total no of counter}}=\frac{4}{9}$

$\frac{g}{g+r}=\frac{4}{9}$

$\Rightarrow 9g=4g+4r$

$\Rightarrow 5g=4r\quad \ldots(i)$

Also if 4 red and 2 green counter is added the probability of drawing a green counter is

$P(g)=\frac{10}{23}=\frac{\text{No of g counter}}{\text{Total no of counter}}$

$\Rightarrow \frac{10}{23}=\frac{g+2}{g+2+r+4}$

$\Rightarrow \frac{10}{23}=\frac{g+2}{g+r+6}$

$\Rightarrow 10g+10r+60=23g+46$

$\Rightarrow 10r+14=13g\ quad \ldots(ii)$

Substitute the value of g in equation (ii)[/tex]

$\Rightarrow 10\times \frac{5}{4}g+14=13g$

$\Rightarrow \frac{25}{2}g+14=13g$

$\Rightarrow g=28$

Therefore $r=35$

Thus there 28 green counter and 35 red counter

6 0

3 years ago