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zhuklara [117]
3 years ago
12

What is the magnitude of the displacement of a car with an acceleration of 3.75 m/s2 as it increases its speed from 5.20m/s to 1

3.5m/s?
Physics
1 answer:
NeX [460]3 years ago
7 0

Answer:

20.7 m

Explanation:

using v^2=u^2+2as

s=(v^2-u^2)/2a

v=13.5

u=5.2

a=3.75

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A ball initially at rest rolls down a hill with an acceleration of 3.3 m/s2. If it accelerates for 7.5 s, how far will it move?
goldfiish [28.3K]

<u>Answer:</u>

  Ball will move 92.8125 meter along the cliff in 7.5 seconds.

<u>Explanation:</u>

We have equation of motion , s= ut+\frac{1}{2} at^2, s is the displacement, u is the initial velocity, a is the acceleration and t is the time.

In this case initial velocity = 0 m/s, acceleration = 3.3 m/s^2, we need to calculate displacement when time = 7.5 seconds.

Substituting

  s=0*7.5+\frac{1}{2} *3.3*7.5^2\\ \\ =92.8125 meter

  So ball will move 92.8125 meter along the cliff in 7.5 seconds.

5 0
3 years ago
What is the power of 10 when 0.00503 is written in scientific notation
Sergeeva-Olga [200]
The answer is 10^-3.
5 0
3 years ago
Unpolarized light with an intensity of (25.0 A) units is passed through two successive polarizing filters, the first with its po
coldgirl [10]

Answer:

the intensity of the light after passing through the two polarizing filters is 4.11 units  

 

Explanation:

Given the data in the question;

the intensity of an unpolarized light; I₀ = 25.0 units

when the unpolarized light passes through the first polarizer, its intensity reduces to half of its initial value;

⇒ I₁ = I₀/2 = 25/2 = 12.5 units

the angle between the transmission axes of two polarizers is;

∅ = 55° - 0° = 55°

The intensity of the light after passing through two polarizing filters will be;

I₂ = I₁cos²∅      

we substitute

I₂ = 12.5 × cos²(55)

I₂ = 12.5 × 0.3289899

I₂ = 4.11 units

Therefore, the intensity of the light after passing through the two polarizing filters is 4.11 units

6 0
3 years ago
The elements in a column of the periodic table _____.
Shtirlitz [24]
C. have similar properties
(this is because they have the same number of electrons in the outer orbital)
7 0
3 years ago
If the average gauge pressure in the vein is 12200 Pa, what must be the minimum height of the bag in order to infuse glucose int
Amanda [17]

Answer:

h = 1.22 m

Explanation:

Given:

Pressure in the vein = 12200 Pa

Specific gravity of the liquid  = 1.02

now,

the pressure due to a fluid is given as:

P = pgh

where,

P is the pressure,

ρ is the density of fluid = specific gravity x density of water = 1.02 x 1000 kg/m³

ρ = 1020 kg/m³

g is the acceleration due to the gravity = 9.81m/s²

h is the height

thus,

h = P/pg =\frac{12200}{1020\times 9.8}=1.22 m

6 0
3 years ago
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