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3 years ago

The graph shows two runners participating in a race.

Physics

2 answers:

luda_lava [24]3 years ago

8 0

Answer: The answer is A

Explanation: Daniela has a 5 meter head start but leonard caught up to her.

qaws [65]3 years ago

3 0

The answer is the first one, Daniela has a 5 meter head start but leonard caught up to her.

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What is a good scientific question on a baloon powered car? (it's for my science fair)

Salsk061 [2.6K]

<u>Answer: </u>

Balloon powered car works on the principle of Newtons III law. Escaping air from the balloon, the car accelerates forward. The reaction is the air behind the car, pushing against it, and with the same force car moves forward is the action.

<em>Some scientific questions are:</em>

1. What is the energy stored in the balloon?

Ans: Potential energy (Potential energy is stored in elastic balloon)

2. Which energy is used in balloon-powered car?

Ans: Kinetic energy. (Whenever the balloon escapes the air, potential energy is converted into Kinetic energy)

3. What is the principle involved in balloon powered car?

Ans: Newtons III law.

6 0

4 years ago

A blender with a total resistance of 6 ohms runs on a voltage of 190 volts. How much current does it use? NEED TO KNOW ASAP PLEA

faltersainse [42]

<h2>Hello!</h2>

The answer is 31.67 Amps.

To solve the problem, we need to use Ohm's Law equation, which states that:

$V=IR$

Where,

V, is the voltage (in volts)

I, is the current (in Amps)

R, is the resistance (in Ohms)

We are given the following information:

$Voltage=190v\\Resistance=6\Omega\\$

So, using Ohm's Law equation and substituting the given information, we have:

$V=IR\\\\190v=I*6\Omega\\\\I=\frac{190v}{6\Omega}=31.67Amps$

Hence, we have that the current used by the blender is 31.67Amps.

Have a nice day!

4 0

3 years ago

Suppose 8.41 moles of a monatomic ideal gas expand adiabatically, and its temperature decreases from 395 to 279 K. Determine (a)

sergeinik [125]

Answer:

a) W=12166.20876 J

b) U= -12166.20876 J

Explanation:

No. of moles, n = 8.41

Change of temperature, ΔT = T1 - T2

= 395 - 279

= 116 K

For monatomic gas, γ = 5/3

γ -1 = 2 /3

Solution:

(a)

Work done, $W= \frac{nR}{\gamma-1}(T_1-T_2)$

plugging values we get

$W= \frac{8.314\times8.41}{2/3}(116)$

Ans: 12166.20876 J

Work done, W = + 12166.20876 J

(b)

From first law of thermodynamics, dQ = U + W

but, dQ = 0 ( adiabatic process)

Hence, U = - W

= - 12166.20876 J

Ans:

Change in internal energy, U = - 12166.20876 J

8 0

3 years ago

A 70kg skier moving at 5 m/sec down a slope what is the skier’s momentum

olga2289 [7]

<u><em>Answer:</em></u>

Momentum of the skier is 350 Kg.m/sec

<u><em>Explanation:</em></u>

<u>Momentum of a body can be calculated using the following rule:</u>

P = m * v

<u>where:</u>

P is the momentum of the body

m is the mass of the body given as 70 Kg

v is the velocity of the body given as 5 m/sec

<u>Substitute with the givens in the above rule to get the momentum of the skier as follows:</u>

P = m * v

P = 70 * 5

P = 350 Kg.m/sec

Hope this helps :)

4 0

3 years ago

A force of 48 newtons is required to start a 5.0 kg box moving across a horizontal concrete floor. What is the coefficient of st

Soloha48 [4]

1) The coefficient of static friction is 0.980

2) The coefficient of kinetic friction is 0.908

Explanation:

In the first situation, the box is still at rest. There are two forces acting on the box:

- The force of push, F, forward

- The force of static friction, $F_f$

Since the box is in equilibrium we have

$F_f = F$ (1)

The value of frictional force changes from zero to a maximum value which is given by:

$F_f = \mu_s mg$ (2)

where

$\mu_s$ is the coefficient of static friction

m is the mass of the box

g is the acceleration of gravity

So, if the force F needed to put the box in motion is 48 N, it means that this is also the maximum value of the force of friction. So, we can combine eq.(1) and (2) to find the coefficient of static friction:

$\mu_s = \frac{F}{mg}$