The remainder represented by synthetic division is -5.
<h3>What is synthetic division?</h3>
Synthetic division can be defined as a simplified way of dividing a polynomial with another polynomial equation of degree 1.
Given
A vertical line and a horizontal line combine to make an L shape.
There are two rows of entries within the shape.
Row 1 has entries 2, 10, 1, 5.
Row 2 has entries blank, -10, 0, -5.
Entry -5 is on the outside to the left of the shape. The entry represents the zero of the divisor. This entry to the variable (assume the variable is x) is;
x + 5 = 0
x = -5
Hence, the divisor of the synthetic division is -5.
To know more about synthetic division click the link given below.
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Answer:
6a) i- 2hrs 36mins ii- 3hrs 12mins
b) car A≈ 76.9km/h car B≈ 62.5km/h
c)------
7a) 35km
b) car A=75km car B=60km
c) 30km
d) car A≈36mins car B≈48mins
Step-by-step explanation:
6a) Using the graph follow the lines until they finish then go downwards until you get to the x-axis. The x-axis is going up by 12mins for each square.
b) Using the answer from a, you divide 200km by the time.
For car A 2hrs 36mins becomes 2.6 because 36mins/60mins=0.6
∴ car A: 200/2.6≈ 76.92km/h
For car B 3hrs 12mins becomes 3.2 because 12mins/60mins=0.2
∴ car B: 200/3.2≈ 62.5km/h
7a) Using the graph go down from where the line of car A finished to meet car B. The y-axis is going up by 5km for each square.
b) Starting from the x-axis at 1 hour go upwards to see where you meet the car B line (60km) and car A line(75km). (sorry if that does not really make sense).
c) Difference from car A line to car B:
155km-125km=30km
d) Going across from 50km meet car A line and go down to see it has been travelling for approx. 36mins. Then continue across to car B line, go down to see it reached 50km at approx. 48mins.
Hope this helps.
Answer:
C
Step-by-step explanation:
Answer:
Length of smaller side = 15 inches
Length of bigger side = 36 inches
Length of hypotenuse = 39 inches
Step-by-step explanation:
Given:
Length of smaller side = a
Length of bigger side = (a + 21) inches
Length of hypotenuse = (a + 24) inches
Find:
Length of all side
Computation:
Using Pythagorean theorem
Hypotenuse² = Base² + Perpendicular²
(a+24)² = a² + (a+21)²
a² + 576 + 48a = a² + a² + 441 + 42a
a² - 6a - 135 = 0
(a-15)(a+7)
So
a = 15 inches a = -7 inches
So,
Length of smaller side = a = 15 inches
Length of bigger side = (a + 21) inches = 15 + 21 = 36 inches
Length of hypotenuse = (a + 24) inches = 15 + 24 = 39 inches
