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vova2212 [387]
2 years ago
7

A piece of magnesium is in the shape of a cylinder with a height of 6.62 cm and a diameter of 2.34 cm. If the magnesium sample h

as a mass of 17.1 g, what is the density of the sample? (formula for volume of a cylinder: volume = r2h)
Chemistry
1 answer:
frez [133]2 years ago
8 0

Answer:

0.600 g/cm³

Explanation:

Step 1: Given data

  • Height of the cylinder (h): 6.62 cm
  • Diameter of the cylinder (d): 2.34 cm
  • Mass of the cylinder (m): 17.1 g

Step 2: Calculate the volume of the cylinder

First, we have to determine the radius, which is half of the diameter.

r = d/2 = 2.34 cm/2 = 1.17 cm

Then, we use the formula for the volume of the cylinder.

V= π × r² × h

V= π × (1.17 cm)² × 6.62 cm

V = 28.5 cm³

Step 3: Calculate the density (ρ) of the sample

The density is equal to the mass divided by the volume.

ρ = m/V

ρ = 17.1 g/28.5 cm³

ρ = 0.600 g/cm³

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lora16 [44]

Answer:

B. Uranium breaks down ti produce heat.

Explanation:

In fission, heavy nucleus split into lighter nucleus.. And energy release in this process in the form of heat.

3 0
2 years ago
Suppose now that you wanted to determine the density of a small crystal to confirm that it is phosphorus. From the literature, y
denis23 [38]

Answer:

Volume of CHCl_3   = 15.31 mL

Volume of CHBr_3 = 4.69 mL

Explanation:

Given that:

the density of the mixture = 1.82 g/mL

From the density of the pure samples

The density of CHCl_3 = 1.492 g/mL

The density of CHBr_3 = 2.890 g/mL

The total volume of the liquid mixture = 20.0 mL

Suppose the volume of  CHCl_3 = P ml

and the volume of CHBr_3 = Q ml

the sum of their volumes should be equal to the total volume of the mixture

P \ ml + Q \ ml = 20 ml  ----- (1)

However, we know that Density = mass/volume

∴ mass = density × volume

The equation can now be expressed as:

\mathtt{(Density \ of  \ CHCl_3 \times Vol. \ of  \ CHCl_3 ) + (Density  \  of \  CHBr_3  \times \ volume \ of \ CHBr_3)} = \mathtt{ (Density  \ of \ mixture \times volume \ of \ the \ mixture)}

1.492 g/mL × P mL + 2.890 g/mL × Q mL = 1.82 g/mL × 20 mL  ---- (2)

From equation (1) ;

let Q = 20 - P

The replace the value of P into equation (2)

1.492 g/mL × P mL + 2.890g/mL × (20 - P) mL = 1.82 g/mL × 20 mL

1.492 P g + 57.8g - 2.890 P g =  36.4g

1.492 P g - 2.890 P g = 36.4g - 57.8g

-1.398 P g = -21.4g

P = -21.4g/-1.398g

P = 15.31 mL

Q = 20 - P

Q = (20 - 15.31) mL

Q = 4.69 mL

∴

Volume of CHCl_3   = 15.31 mL

Volume of CHBr_3 = 4.69 mL

6 0
3 years ago
Consider a reactant with an order of 1: What effect does that reactant have on the rate equation when the concentration is doubl
____ [38]

Answer:

1) The reaction rate is double with respect to that reactant

Explanation:

Hello,

By considering the rate law:

-r_A=kC_A

If we double the reactant A concentration, by definition, the rate will be doubled as well since the C_A power is one (order 1), this could be proved just by checking it out in the rate law.

Best regards.

6 0
3 years ago
When two moles of ethane react completely with oxygen, how many moles of carbon dioxide will be produced?A. 2.B. 4.C. 8.D. Unkno
babymother [125]

Answer:

Option B.

Explanation:

As any reaction of combustion, the O₂ is a reactant and the products are CO₂ and H₂O. Combustion reaction for ethane is:

2C₂H₆  +  7O₂   →   4CO₂  +  6H₂O

So 2 moles of ethane react with 7 moles of oxygen to make 4 moles of dioxide and 6 moles of water.

Then 2 moles of ethane will produce 4 moles of CO₂

6 0
2 years ago
This chart shows descriptions of the atoms for four different substances.
Whitepunk [10]
I think it’s Object 3
Hopefully this helps
8 0
2 years ago
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