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castortr0y [4]
3 years ago
5

How much power does it take to lift 30.0 kg 100 m high in 5.00 s?

Physics
1 answer:
zheka24 [161]3 years ago
5 0

._.Answer:.

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Explanation:.

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When the parachute opens, the air resistance increases. The skydiver slows down until a new, lower terminal velocity is reached.

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Which of the following best describes acceleration?
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the rate of change of velocity

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When an object of mass m1 is hung on a vertical spring and set into vertical simple harmonic motion, it oscillates at a frequenc
Arlecino [84]

Answer:

m_2/m_1=9.745

The ratio m_2/m_1 of the masses is 9.745

Explanation:

Formula for frequency when mass m_1 is hung on the spring:

f_1=\frac{1}{2\pi}\sqrt{\frac{k}{m_1}}

where:

k is the spring constant

Formula for frequency when mass m_2 is hung on the spring along with m_1:

f_2=\frac{1}{2\pi}\sqrt{\frac{k}{m_1+m_2}}

where:

k is the spring constant.

In order to find ratio m_2/m_1, Divide the above equations:

\frac{f_1}{f_2} =\frac{ \frac{1}{2\pi}\sqrt{\frac{k}{m_1}}}{\frac{1}{2\pi}\sqrt{\frac{k}{m_1+m_2}}}

On Solving the above equation:

\frac{f_1}{f_2} =\frac{\sqrt{\frac{k}{m_1}}}{\sqrt{\frac{k}{m_1+m_2}}}\\(\frac{f_1}{f_2})^{2} =\frac{m_1+m_2}{m_1} \\(\frac{11.8}{3.60})^2= \frac{m_1+m_2}{m_1} \\10.745=\frac{m_1+m_2}{m_1}\\10.745m_1=m_1+m_2\\m_2=10.745m_1-1m_1\\m_2/m_1=9.745

The ratio m_2/m_1 of the masses is 9.745

8 0
4 years ago
You drive a car 660 m to the east, then 400 m to the north. What is the magnitude of your displacement? Using a sketch, estimate
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Explanation:

You walk 53m to the north, then you turn 60° to your right and walk another 45m. Determine the direction of your displacement vector. Express your answer as an angle relative to east.

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A sport car starts from rest with an acceleration of 12 m/s2 . Calculate its final velocity after 7 s.
miv72 [106K]

Answer:

Final velocity= 84 m/s

Explanation:

V final= V initial + a * t

Vf = 0+ 12 (7)

Vf= 84 m/s

4 0
3 years ago
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