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Julli [10]
2 years ago
7

A plane opens a parachute after it lands inorder to

Physics
2 answers:
Elis [28]2 years ago
8 0

Answer:

When the parachute opens, the air resistance increases. The skydiver slows down until a new, lower terminal velocity is reached.

Andreas93 [3]2 years ago
7 0

Answer:

salamat sapoints po lods salamat sapoints po lods thaks

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A student noted that the sign shown here is always associated with a wheelchair ramp at or near a staircase or entrance steps. W
Vitek1552 [10]

The main reason why wheelchair ramps are used to move people up a staircase is because it has a high mechanical advantage which leads to a greater efficiency in moving people up the staircase.

  • <em>Let the height of the staircase = h</em>
  • <em>Let the length of the ramp = L</em>

The mechanical advantage of the ramp is calculated as follows;

M.A = \frac{L}{h}

As the length of the ramp increases, people will be move up to a greater distance up the staircase.

Thus, the main reason why wheelchair ramps are used to move people up a staircase is because it has a high mechanical advantage which leads to a greater efficiency in moving people up the staircase.

Learn more about mechanical advantages of ramps here: brainly.com/question/200179

3 0
2 years ago
A model airplane with a mass of 0.741kg is tethered by a wire so that it flies in a circle 30.9 m in radius. The airplane engine
liq [111]

(a) 24.6 Nm

The torque produced by the net thrust about the center of the circle is given by:

\tau = F r

where

F is the magnitude of the thrust

r is the radius of the wire

Here we have

F = 0.795 N

r = 30.9 m

Therefore, the torque produced is

\tau = (0.795 N)(30.9 m)=24.6 N m

(b) 0.035 rad/s^2

The equivalent of Newton's second law for a rotational motion is

\tau = I \alpha

where

\tau is the torque

I is the moment of inertia

\alpha is the angular acceleration

If we consider the airplane as a point mass with mass m = 0.741 kg, then its moment of inertia is

I=mr^2 = (0.741 kg)(30.9 m)^2=707.5 kg m^2

And so we can solve the previous equation to find the angular acceleration:

\alpha = \frac{\tau}{I}=\frac{24.6 Nm}{707.5 kg m^2}=0.035 rad/s^2

(c) 1.08 m/s^2

The linear acceleration (tangential acceleration) in a rotational motion is given by

a=\alpha r

where in this problem we have

\alpha = 0.035 rad/s^2 is the angular acceleration

r = 30.9 m is the radius

Substituting the values, we find

a=(0.035 rad/s^2)(30.9 m)=1.08 m/s^2

4 0
3 years ago
a bucket of unstretched springs (k=8 N/m) resting on the ground.Calculate the bucket's Mechanical Energy in [J}
Flura [38]

Answer:

0 J

Explanation:

The mechanical energy of a spring is given by 0.5kx^{2} where k is spring constant and x is extension of spring. Since the spring is unstretched,  its extension is zero.

#Notice that the potential energy is 0.

-Substituting spring constant,  k with 8 and extension with zero then the mechanical energy will be

0.5\times 8\times 0^{2}=0 J

6 0
3 years ago
(c) 1+i<br>0. If 2ncz : nc2<br>= 12:1, then the value of n will be<br>(d) n=2​
d1i1m1o1n [39]

Answer:

hey hi ......✌✌✌......

3 0
2 years ago
A car traveled 140 km in 2.5 hours. What was its average speed in km per hour?
Vilka [71]
<h3>formula of speed is distance/time</h3><h3>so</h3><h2>140/2.5</h2><h2>= 56</h2><h2>the answer should be </h2><h2>56 km/h</h2>

5 0
2 years ago
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