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Julli [10]
3 years ago
7

A plane opens a parachute after it lands inorder to

Physics
2 answers:
Elis [28]3 years ago
8 0

Answer:

When the parachute opens, the air resistance increases. The skydiver slows down until a new, lower terminal velocity is reached.

Andreas93 [3]3 years ago
7 0

Answer:

salamat sapoints po lods salamat sapoints po lods thaks

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A uniform cubical crate is 0.740 m on each side and weighs 600 N. It rests on the floor with one edge against a very small, fixe
Sindrei [870]

Answer:

H = 0.673

Explanation:

given,

side of cubical crate = 0.74

weight of the crate = 600 N

magnitude of force = 330 N

the Horizontal distance of its Center of mass

= 0.74/2

= 0.37

Let the required Height be H

By Balancing the Torques, we get

H x 330 N = 0.37 x 600

330 H = 222

H = 0.673

hence, the height above the floor where force is acting is equal to 0.673 m

6 0
3 years ago
A collision between two moving objects can be represented on a position-time graph.
nexus9112 [7]

Answer:

the correct answer is false

Explanation:

3 0
3 years ago
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Finish my home work please
RUDIKE [14]
For number 3 the answer is solid: pizza
 liquid: smoothie
gas: air diffuser
8 0
3 years ago
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Which of the following describes a physical change? A. A marshmallow burns over an open flame. B. Icicles melt from a rooftop. C
AnnZ [28]

Answer:

B

Explanation:

Icicles melt from a rooftop

5 0
3 years ago
A mass spectrometer is being used to separate common oxygen-16 from the much rarer oxygen-18, taken from a sample of old glacial
Mashcka [7]

Answer: 0.076 m

Explanation:

Magnetic force= centripetal force;

F(B) = F(c) --------------------------(1)

Bqv= mv^2/R---------------------(2)

Where B= magnetic field,q= charge, = mass, R= radius of the circular path.

Radius of the circular path,R= mv/qB.

Mass of oxygen-16 is 2.66e−26kg, and they are singly charged = 18/16(mass ratio= 18:16)

18/16 × (2.26 × 10^ -26 kg)

= 2.99 × 10^26 kg

∆d=2r(18)-2r(16)-----------------(3)

r(18) is the radius of mass of oxygen-18,

r(16) is the radius of mass of oxygen-16.

From the question, v= 3.7×10^6 m/s, q= 1.6×10^-9 C.

From equation (2) above we have;

R= MV/qB------------------------(4)

This equation (4) is used in solving for the distance between the two.

Solving;∆d=2r(18)-2r(16)

∆d = 2[m(18) - m(16)] v/ qB

M(18)-m(16) =(2.99-2.66)× 10^-26:

qB= 1.6×10^-19×2 = 3.2×10^-19

= (2.99-2.66)× 10^-26/ 3.2× 10^-19

= 0.076 m

7 0
3 years ago
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