By weighted average method, the x-coordinates of the center of mass of the compound figure, the uniform thin L-shaped construction brace is
meters.
<h3>How to determine the coordinates of the center of mass of a compound figure </h3>
Let suppose that the entire construction has a <em>uniform</em> mass, then the coordinates of the center of mass can be determined by definition of <em>weighted</em> average:
(1)
(2)
If we know that a = 2.20 m and b = 1.63 m, then the x-coordinates of the center of mass of the compound figure is:

By weighted average method, the x-coordinates of the center of mass of the compound figure, the uniform thin L-shaped construction brace is
meters.
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We are given with:
Sensitivity: 100uJ/cm2
Diameter: 10mm
Background Optical Power: 8uW
Source Optical Power: 50uW
Required: exposure time
Solution:
Exposure time = sensitivity x area / (background power - source power)
= 100uJ/cm2 (π/4) (1 cm)² / (80 uW - 50 uW)
= 2.62 s
The exposure time is 2.62 seconds.
Answer:
Length (L2) = 0.51m
Wavelength of string (∆) = 1.02m
Wavelength of sound produced = 0.7795m
Explanation:
Using the equation L1F1 = L2F2
L1 = 0.68m, F1 = 330Hz, F2 = 440Hz
Therefore, (0.68m)(330Hz) = (L2)(440Hz)
L2 = 0.68m × 330hz/440hz
L2 = 0.51m
0.68m - 0.51m = 0.17m from the but
B. ∆ = 2×length (L2)
∆ = 2(0.51) = 1.02m
C. Frequency (f) = 440Hz
V = ∆f
343m/s =∆×440hz
∆ = 343m/s/440hz
∆ = 0.7795m
A jet stream forms high in the upper troposphere between two air masses of very different temperature. The greater the temperature difference between the air masses, the faster the wind blows in the jet stream.
.
.
So "Differences in temperature between two air masses" is the answer
Answer:
2.97 meters
9.85 m/s^2
Explanation:
Given that :
Period (T1) = 3.45 seconds
When length , l is shortened by 1m, period (T2) = 2.81 seconds
Using the relation :
T = 2π√l/g
g = acceleration due to gravity
T1 = 2π√L/g - - - - (1)
Period 2:
x = shortened length = 1m
T2 = 2π√L-x/g - - - (2)
Square both sides
T1² = (2π)² L/g - - - (3)
T2² = (2π)² L-x/g - - (4)
Divide 3 and 4
(T2/T1)² = (L-x) / L
(2.81/3.45)^2 = (L - 1) / L
0.6633984 = (L - 1) / L
0.6633984L = L - 1
0.6633984L - L = - 1
−0.336601L = - 1
L = 1 / 0.336601
L = 2.9708764
Length = 2.97 meters
Acceleration due to gravity :
g = L(2π/T1)^2
g = 2.97(2π / 3.45)^2
g = 2.97 * 3.3168172
g = 9.8509
g = 9.85 m/s^2
g