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zlopas [31]
3 years ago
5

Nathan is walking to the store and sees a snake slithering across the sidewalk. He jumps over it with an initial vertical veloci

ty of 10 ft/s. How long does it take for Nathan to land back on the ground
Physics
1 answer:
Travka [436]3 years ago
8 0

Answer:

0.62\:\mathrm{s}

Explanation:

Since the universal SI unit for velocity is meters/second, let's convert ft/s to m/s:

10\:\mathrm{ft/s}=3.048\:\mathrm{m/s}

We can use the following kinematics equation to solve this question:

v_f=v_i+at

What we know:

  • The initial velocity, v_i, is 3.048\:\mathrm{m/s}
  • (physics concept) The final velocity must be equal in magnitude but opposite in direction to the initial velocity (v_f=-3.048\:\mathrm{m/s})
  • Acceleration, a, is acceleration due to gravity at about 9.8\:\mathrm{m/s}

Solving for t:

-3.048=3.048+(-9.8t),\\-6.096=-9.8t,\\t=\frac{-6.096}{-9.8}\approx \boxed{0.62\:\mathrm{s}}

You might be interested in
Determine the CM of the uniform thin L-shaped construction brace shown in (Figure 1) . Suppose that a = 2.20 m and b = 1.63 m De
aleksandrvk [35]

By weighted average method, the x-coordinates of the center of mass of the compound figure, the uniform thin L-shaped construction brace is \bar x = \frac{1.10\cdot m_{A}+2.10\cdot m_{B}}{m_{A}+m_{B}} meters.

<h3>How to determine the coordinates of the center of mass of a compound figure </h3>

Let suppose that the entire construction has a <em>uniform</em> mass, then the coordinates of the center of mass can be determined by definition of <em>weighted</em> average:

\bar x = \frac{\sum \limits_{i = 1}^{n}x_{i}\cdot m_{i}}{\sum \limits_{i=1}^{n}m_{i}}     (1)

\bar y = \frac{\sum \limits_{i = 1}^{n}y_{i}\cdot m_{i}}{\sum \limits_{i=1}^{n}m_{i}}     (2)

If we know that a = 2.20 m and b = 1.63 m, then the x-coordinates of the center of mass of the compound figure is:

\bar x = \frac{1.10\cdot m_{A}+2.10\cdot m_{B}}{m_{A}+m_{B}}

By weighted average method, the x-coordinates of the center of mass of the compound figure, the uniform thin L-shaped construction brace is \bar x = \frac{1.10\cdot m_{A}+2.10\cdot m_{B}}{m_{A}+m_{B}} meters.

To learn more on center of mass: brainly.com/question/8662931

#SPJ1

8 0
2 years ago
d) Provided a recording medium (film) with sensitivity of 100uJ/cm2 and a power detector with 10mm of diameter, background measu
lara31 [8.8K]
We are given with:
Sensitivity: 100uJ/cm2
Diameter: 10mm
Background Optical Power: 8uW
Source Optical Power: 50uW

Required: exposure time

Solution:
Exposure time =  sensitivity x area / (background power - source power)
= 100uJ/cm2 (π/4) (1 cm)² / (80 uW - 50 uW)
= 2.62 s

The exposure time is 2.62 seconds.
3 0
3 years ago
An unfingered guitar string is 0.68 m long and is tuned to play E above middle C (330 Hz).
dem82 [27]

Answer:

Length (L2) = 0.51m

Wavelength of string (∆) = 1.02m

Wavelength of sound produced = 0.7795m

Explanation:

Using the equation L1F1 = L2F2

L1 = 0.68m, F1 = 330Hz, F2 = 440Hz

Therefore, (0.68m)(330Hz) = (L2)(440Hz)

L2 = 0.68m × 330hz/440hz

L2 = 0.51m

0.68m - 0.51m = 0.17m from the but

B. ∆ = 2×length (L2)

∆ = 2(0.51) = 1.02m

C. Frequency (f) = 440Hz

V = ∆f

343m/s =∆×440hz

∆ = 343m/s/440hz

∆ = 0.7795m

3 0
3 years ago
What causes the jet stream? A. Differences in altitude between two air masses B. Differences in temperature between two air mass
padilas [110]
A jet stream forms high in the upper troposphere between two air masses of very different temperature. The greater the temperature difference between the air masses, the faster the wind blows in the jet stream.
.
.
So "Differences in temperature between two air masses" is the answer
3 0
4 years ago
A simple pendulum has a period of 3.45 seconds. When the length of the pendulum is shortened by 1.0m,the period is 2.81 seconds,
pochemuha

Answer:

2.97 meters

9.85 m/s^2

Explanation:

Given that :

Period (T1) = 3.45 seconds

When length , l is shortened by 1m, period (T2) = 2.81 seconds

Using the relation :

T = 2π√l/g

g = acceleration due to gravity

T1 = 2π√L/g - - - - (1)

Period 2:

x = shortened length = 1m

T2 = 2π√L-x/g - - - (2)

Square both sides

T1² = (2π)² L/g - - - (3)

T2² = (2π)² L-x/g - - (4)

Divide 3 and 4

(T2/T1)² = (L-x) / L

(2.81/3.45)^2 = (L - 1) / L

0.6633984 = (L - 1) / L

0.6633984L = L - 1

0.6633984L - L = - 1

−0.336601L = - 1

L = 1 / 0.336601

L = 2.9708764

Length = 2.97 meters

Acceleration due to gravity :

g = L(2π/T1)^2

g = 2.97(2π / 3.45)^2

g = 2.97 * 3.3168172

g = 9.8509

g = 9.85 m/s^2

g

4 0
3 years ago
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