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victus00 [196]
2 years ago
15

A Navy vessel is traveling due north during wartime. A torpedo has been launched by an enemy directly toward the stern (rear) of

the vessel. Can the vessel outrun the torpedo if both continue in a straight line due north?
A) Yes, the Navy vessel is faster

B) No, the Navy vessel is slower

C) Maybe, since both travel at the same speed

D) Maybe, based on the temperature of the water
Physics
1 answer:
Anika [276]2 years ago
8 0

Answer:

The correct option is;

B) No, the Navy vessel is slower

Explanation:

The speed of some torpedoes can be as high as 370 km/h. The average speed of a fast Navy vessel is approximately 110 km/h

Therefore, the torpedoes travel approximately 3 times as fast as the (slower) Navy vessel, such that the torpedo covers three times the distance of the Navy vessel in the same time and therefore, if the Navy vessel and the torpedo continue in a straight line (in the same direction) due north the vessel can not outrun the torpedo

Therefore, no the Navy vessel travels slower than a torpedo.

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The current through the circuit element will also be doubled.

Explanation:

The relationship between voltage and current of a circuit element is given by Ohm's Law. According to Ohm's Law:

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If the resistance of the element is kept constant, the relation between Voltage and Current through that element becomes as follows:

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Thus, the voltage is directly proportional to the current for constant value of the resistance.

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You place a box weighing 200.2 N on a inclined plane that makes a 37.1 angle with the horizontal. Compute the component of the g
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141.56 N.

Explanation:

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Weight of the box= 200.2 N

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Solution;

Gravitational force on the box, F_g= weight of the box

                                                                           = 200.2 N

Component of gravitational force along plane = F_g * sin( ∅ )

                                                                                   = W * (sin∅)

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