A Navy vessel is traveling due north during wartime. A torpedo has been launched by an enemy directly toward the stern (rear) of
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Answer:
Final temperature, T2 = 314.9 Kelvin
Explanation:
Given the following data:
Mass = 0.9kg
Initial temperature, T1 = 10°C to Kelvin = 10 + 273 = 283K
Quantity of heat = 120,000 J
Specific heat capacity = 4182 j/kgK
To find the final temperature;
Heat capacity is given by the formula;
Where;
Q represents the heat capacity or quantity of heat.
m represents the mass of an object.
c represents the specific heat capacity of water.
dt represents the change in temperature.
Making dt the subject of formula, we have;
Substituting into the equation, we have;
dt = 31.9K
Now, the final temperature T2 is;
But, dt = T2 - T1
T2 = dt + T1
T2 = 31.9 + 283
T2 = 314.9 Kelvin
Answer:
v₃ = 3.33 [m/s]
Explanation:
This problem can be easily solved using the principle of linear momentum conservation. Which tells us that momentum is preserved before and after the collision.
In this way, we can propose the following equation in which everything that happens before the collision will be located to the left of the equal sign and on the right the moment after the collision.
where:
m₁ = mass of the car = 1000 [kg]
v₁ = velocity of the car = 10 [m/s]
m₂ = mass of the truck = 2000 [kg]
v₂ = velocity of the truck = 0 (stationary)
v₃ = velocity of the two vehicles after the collision [m/s].
Now replacing: