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3 years ago

A baseball weighing 0.5 kg falls from the sky. You hit it with a bat with a force of 50 N at an upward angle of 45°.

Physics

1 answer:

kirill [66]3 years ago

6 0

Answer:

bchfdfu

hjoufu I'm not sure if you are still interested in the position and would like to know if you are interested

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What are the visible and invisible forms of moisture in the air?

Usimov [2.4K]

The invisible form is water vapor that is microscopic and found all around us. When the air is really hot you can see this water vapor above ground as if it's moving. The visible form is either water droplets that fall down as rain, or it's the clouds that are basically a form of moisture that is iced up because it's very cold so it condensed and formed a cloud.

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4 years ago

Read 2 more answers

The decomposition of sulfuryl chloride (so2cl2) is a first-order process. the rate constant for the decomposition at 660 k is 4.

Natali5045456 [20]

THIS IS A GAS PHASE REACTION AND WE ARE GIVE PARTIAL PRESSURES . I WRITE IN TERMS OF P RATHER THAN CONCENTRATION : lnPso2cl12=-kt+lnPso2cl1 initial partial pressure Pso2cl12 the rate constant k and the time t lnPso2cl12=(4.5*10-2*s-1)*65*s+ln (375) so lnPso2cl12=3.002 we take the base e antilog: lnPso2cl12=e3.002 Pso2cl12=20 torr we use the integrated first order rate lnPso2cl12=3.002=k*t+ lnPso2cl12=3.002 we use the same rate constant and initial pressure k=4.5*10-2*s-1 Pso2cl12=375 Pso2cl12=1* so2cl12 Pso2cl12=37.5 torr subtract in Pso2cl12 grom both side lnPso2cl12- lnPso2cl12=-kt ln(x)-ln(y)=ln (x/y) ln (Pso2cl12/Pso2cl20)=-kt we get t -1/k*ln(Pso2cl12/Pso2cl20)=t t=51 s

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3 years ago

What is the minimum value of the friction coefficient between the boxes that will keep them from slipping when the 100 N force i

CaHeK987 [17]

Answer:

The friction coefficient's minimum value will be "0.173".

Explanation:

The given query seems to be incomplete. Below is the attached file of the complete question.

According to the question,

(a)

The net friction force's magnitude will be:

⇒ $F_{net}=ma$

$=5\times 1.7$

$=8.5 \ N$

(b)

For m₃,

⇒ $ma=\mu m_3 g$

Or,

⇒ $\mu=\frac{a}{g}$

$=\frac{1.7}{9.8}$

$=0.173$

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3 years ago

Which physical properties can be used to identify an unknown substance?

Natalija [7]

Density and boilind point

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3 years ago

If you push a 900N refrigerator with the same force as you lift a 40N dumbbell, the dumbbell will move faster. According to Chap

Yuki888 [10]

Answer:

Second Newton's law

Explanation:

Second Newton's law states that the acceleration of an object is related to the mass of an object and the force applied to it by:

$F=ma$

where

F is the net force applied to an object

m is the mass of the object

a is the acceleration

The equation can be rewritten also as

$a=\frac{F}{m}$ (1)

we see that the acceleration is directly proportional to the force applied, F, and inversely proportional to the mass of the object, m.

In this problem, the force applied to the two objects (refrigerator and dumbbell) is the same, so we must look at their mass. Their mass can be found starting from their weight, which we know:

- refrigerator: $m=\frac{W}{g}=\frac{900 N}{9.8 m/s^2}=91.8 kg$

- dumbbell: $m=\frac{W}{g}=\frac{40 N}{9.8 m/s^2}=4.1 kg$

The dumbbell has a smaller mass, therefore by looking at formula (1), we can see that it will have more acceleration, and this is why it will move faster.

3 0

3 years ago