The equation is as follows;
2CH3OH(g) = 2CH4(g) + O2(g), ΔH= +252.8 kJ
From the equation; for the reaction to produce 2 moles of methane (32g) an energy of 252.8 kJ is released.
Therefore; for an energy of 82.3 kJ the number of moles that will be produced will be; = (2×82.3)/252.3
= 0.6524 moles
which is equivalent to 0.6524 × 16 = 10.438 g
There, the mass of CH4 produced will be 10.438 g
Answer:
The unknown substance is Au ( gold)
Explanation:
SiO2 has a high melting point, is insoluble in water but is a very poor conductor. So the statements do not apply here.
F2 is soluble in water, has a melting point way lower than 1064 °C, and isa gas. F2 doesn't apply here.
Au is insoluble in water, has a high melting point, is a good conductor and is hard. Gold applies are all those statements.
Kbr is good soluble in water, and is a bad conductorbecause it is just a powder, and the molecules have no mobility, and therefore it cannot conduct electricity. The unknown substance is not Kbr.
The unknown substance is Au ( gold)
Four Consecutive terms are written as a-3, a-1, a+1,a+3. So
Sum of Terms : 4a=28
a=7
So the terms are 4,6,8,10
Verification : 4^2+6^2+8^2+10^2
= 216
Answer: This is because, the stem symbolises the bronchioles of the lung through which oxygen is transfered to the lungs. The grabes represent the lungs, left and right respectively.
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