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Free_Kalibri [48]
4 years ago
8

Scoring Scheme: 3-3-2-1 Part I. How many mL of 6 M NaOH stock solution should be used to prepare the 500 mL of 0.2 M NaOH? Pleas

e enter your answer to a tenth of a mL, e.g. 10.3 mL. mL of 6M NaOH =__________.
Chemistry
1 answer:
Orlov [11]4 years ago
4 0

Answer : The volume of 6M NaOH stock solution is, 16.7 mL

Explanation :

To calculate the volume of NaOH stock solution, we use the equation given by neutralization reaction:

M_1V_1=M_2V_2

where,

M_1\text{ and }V_1 are the molarity and volume of NaOH stock solution.

M_2\text{ and }V_2 are the molarity and volume of NaOH.

We are given:

M_1=6M\\V_1=?\\M_2=0.2M\\V_2=500mL

Putting values in above equation, we get:

6M\times V_1=0.2M\times 500mL\\\\V_1=16.7mL

Thus, the volume of 6M NaOH stock solution is, 16.7 mL

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7 0
3 years ago
How many formula units of CaO are in 32.7 g of CaO?
max2010maxim [7]

Answer:

3.51× 10²³ formula units

Explanation:

Given data:

Mass of CaO = 32.7 g

Number of formula units = ?

Solution:

First of all we will calculate the number of moles.

Number of moles = mass/molar mass

Number of moles = 32.7 g/ 56.1 g/mol

Number of moles = 0.583 mol

Number of formula units:

1 mole = 6.022 × 10²³ formula units

0.583 mol ×  6.022 × 10²³ formula units / 1 mol

3.51× 10²³ formula units

The number 6.022 × 10²³ is called Avogadro number.

7 0
3 years ago
Please help! brainliest, rattings, thanks, etc.
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3 0
3 years ago
15 POINTS!!!
lawyer [7]

<em>Answer:</em>

  • At 60 centigrade, the kinetic energy of the substance will be greatest.

<em>Explanation:</em>

As we know, the kinetic energy of substance is directly proportional to Temperature.

The total Kinetic energy can be calculated as follow

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7 0
3 years ago
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Nitrogen has two isotopes. One has an atomic mass of 14.003
Ilia_Sergeevich [38]

Answer:

d= 14.007 amu

Explanation:

Abundance of N¹⁴ = 99.63%

Abundance of N¹⁵ = 0.37%

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Atomic mass of N¹⁵ = 15.000 amu

Average atomic mass = ?

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Average atomic mass = (14.003 × 99.63)+(15.000× 0.37) /100

Average atomic mass =  1395.12 + 5.55 / 100

Average atomic mass  = 1400.67/ 100

Average atomic mass = 14.007 amu.

6 0
3 years ago
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