Question

Scoring Scheme: 3-3-2-1 Part I. How many mL of 6 M NaOH stock solution should be used to prepare the 500 mL of 0.2 M NaOH? Please enter your answer to a tenth of a mL, e.g. 10.3 mL. mL of 6M NaOH =__________.

Answer 1

Answer : The volume of 6M NaOH stock solution is, 16.7 mL

Explanation :

To calculate the volume of NaOH stock solution, we use the equation given by neutralization reaction:

$M_1V_1=M_2V_2$

where,

$M_1\text{ and }V_1$ are the molarity and volume of NaOH stock solution.

$M_2\text{ and }V_2$ are the molarity and volume of NaOH.

We are given:

$M_1=6M\\V_1=?\\M_2=0.2M\\V_2=500mL$

Putting values in above equation, we get:

$6M\times V_1=0.2M\times 500mL\\\\V_1=16.7mL$

Thus, the volume of 6M NaOH stock solution is, 16.7 mL