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Sauron [17]
3 years ago
7

B. Mills works as a construction worker. He makes a salary of 54,200 a year. After

Mathematics
1 answer:
larisa86 [58]3 years ago
4 0

Answer:

$56,097

Step-by-step explanation:

First, we have to figure out how much his raise was, so we can convert 3.5% directly to a decimal:

3.5% = 0.035

Then we find

3.5% of 54,200 = 0.035 x 54,200 = 1,897

1,897 + 54,200 = 56,097

So, Mills new salary is $56,097

hope this helps:)

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VLD [36.1K]
Let’s see, for 6 servings he needed 4 carrots, meaning every carrot was equal to 1.5 servings. 15/1.5 is 10, 10 carrots for 15 servings.
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3 years ago
The random variable x has the following probability distribution: x f(x) 0 .25 1 .20 2 .15 3 .30 4 .10 a. Is this probability di
Reptile [31]

Answer and Explanation:

Given : The random variable x has the following probability distribution.

To find :

a. Is this probability distribution valid? Explain and list the requirements for a valid probability distribution.

b. Calculate the expected value of x.

c. Calculate the variance of x.

d. Calculate the standard deviation of x.

Solution :

First we create the table as per requirements,

x      P(x)         xP(x)           x²            x²P(x)

0    0.25           0               0                0

1     0.20        0.20             1              0.20

2    0.15          0.3               4             0.6

3    0.30         0.9               9             2.7

4    0.10          0.4               16             1.6

   ∑P(x)=1     ∑xP(x)=1.8               ∑x²P(x)=5.1

a) To determine that table shows a probability distribution we add up all five probabilities if the sum is 1 then it is a valid distribution.

\sum P(X)=0.25+0.20+0.15+0.30+0.10

\sum P(X)=1

Yes it is a probability distribution.

b) The expected value of x is defined as

E(x)=\sum xP(x)=1.8

c) The variance of x is defined as

V=\sum x^2P(x)-(\sum xP(x))^2\\V=5.1-(1.8)^2\\V=5.1-3.24\\V=1.86

d) The standard deviation of x is  defined as

\sigma=\sqrt{V}

\sigma=\sqrt{1.86}

\sigma=1.136

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Answer:

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