In the  plane, we have
 plane, we have  everywhere. So in the equation of the sphere, we have
 everywhere. So in the equation of the sphere, we have

which is a circle centered at (2, -10, 0) of radius 4.
In the  plane, we have
 plane, we have  , which gives
, which gives

But any squared real quantity is positive, so there is no intersection between the sphere and this plane.
In the  plane,
 plane,  , so
, so

which is a circle centered at (0, -10, 3) of radius  .
.
 
        
             
        
        
        
Answer:
X = 25
Step-by-step explanation:
Set up as a ratio:
Simplify ratio, multiply by 5, divide by 12

 
        
             
        
        
        
Answer:
 the answer here is number 4
 
        
             
        
        
        
Answer: and the answer is 2x + 7
Step-by-step explanation:
as it is a polynomial in one variable, it has only one solution.
Hope it helped u,
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