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2 years ago

A 78-kg skydiver has a speed of 62 m/s , what is the kinetic energy?

Physics

2 answers:

Cloud [144]2 years ago

3 0

Answer:

149,916J

Explanation:

Pneumonic device: Kevin is half-mad and very square

this translates to: KE=(1/2)mv^2 !!

KE=(1/2)(78)(62^2)

KE=(39)(3844)

KE=149,916 Joules

Fofino [41]2 years ago

3 0

Answer:

it's 149916

Explanation:

Formula = 1/2 x m x v^2

so if you put into your calculator 1/2 x 78 x 62^2

you get 149916

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Answer

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v = 6.59 m/s

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$f_1 = 440Hz$

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For the particular case we have two possible frequencies:

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$f_{bat} = |(440 - 2.1)|$

$f_{bat} = 437.9Hz$

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A 78-kg skydiver has a speed of 62 m/s , what is the kinetic energy?​

A 78-kg skydiver has a speed of 62 m/s , what is the kinetic energy?