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LuckyWell [14K]
3 years ago
9

How does a magnet separate mixtures like sand and iron filings?​

Chemistry
2 answers:
zmey [24]3 years ago
8 0
Because iron filings are magnetic, but sand is not, so the magnet separates the filings from the sand due to magnetic attraction
algol133 years ago
6 0

Answer:

because iron is magnetic and sand is not

Explanation:

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ASAP MULTIPLE CHOICE
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The mass of electrons , i just did the same test and got it right
7 0
2 years ago
Write a sentence or mathematical expression that relates each of the
11111nata11111 [884]

Answer:

Mass to moles: mass/molar mass=mole

Moles to mass: moles x molar mass = mass

Moles to particles:1mole = 6.022x10^23 particles

Particles to moles: 1 particle =1/(6.022x10^23) mole

Explanation:

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2 years ago
A chef fills a 50ml container with 43.5g of cooking oil. whats the density of the oil
jasenka [17]
I believe the answer is .87g/mL. But I'm not sure so whatevs
4 0
3 years ago
You have 55 grams of glucose(C6H12O6). How many grams of oxygen do you have?
zubka84 [21]

Answer:

Mass of oxygen in glucose = 29.3g

Explanation:

Mass of glucose given is 55grams.

We are to find the mass of oxygen in this compound.

In the compound we have 6 atoms of oxygen.

Solution

To find the mass of oxygen in glucose, we calculate the formula mass of glucose. We now divide the formula mass of the oxygen atom with that of the glucose and multiply by the given mass to find the unkown mass.

Atomic mass of C = 12g

                           H = 1g

                           O = 16g

Formula mass of C₆H₁₂O₆ = {(12x6) + (1x12) + (16x6)} = 180

             Mass of O in glucose = \frac{6x16}{180}  x 55

                                                  = \frac{96}{180} x 55

                                                  = 0.53 x 55

            Mass of oxygen in glucose = 29.3g

8 0
3 years ago
The reaction 2a → a2​​​​​ was experimentally determined to be second order with a rate constant, k, equal to 0.0265 m–1min–1. if
olga nikolaevna [1]
According to the second order formula:
1/[At] = K t + 1/[Ao]
and when we have the K constant =0.0265 & we have t = 180 min & we have the initial concentration of A = 4.25 so by substitution:

1/[At]  = 0.0265 X 180min + 1/4.25 
1/[At] = 5
∴[At] = 1/5 = 0.2 m
7 0
3 years ago
Read 2 more answers
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