All categories

3 years ago

How does a magnet separate mixtures like sand and iron filings?

2 answers:

8 0

Because iron filings are magnetic, but sand is not, so the magnet separates the filings from the sand due to magnetic attraction

algol133 years ago

6 0

Answer:

because iron is magnetic and sand is not

Explanation:

You might be interested in

2 moles Na = ______ atoms Na. I need help to figure out the number of atoms in Avogadro's number

Reil [10]

Answer:

12.044 x 10^23 atoms Na

Explanation:

1 mol Na has 6.022 x 10^23 atoms of Na

2 moles Na have 2 x NA = 2 x 6.022 x10^23 atoms Na

4 0

3 years ago

Read 2 more answers

How many equivalent resonance forms can be drawn for so2 without expanding octet on the sulfur atom? (sulfur is the central atom

jok3333 [9.3K]

2 resonance structure.
O=S⁺-O⁻ and O⁻-S⁺=O, angles between S and O are 120°, bond order is 1,5.

4 0

3 years ago

Read 2 more answers

How do rivers affect watersheds?

beks73 [17]

Answer:

Explanation:

the last one I read it

5 0

3 years ago

Read 2 more answers

For the reaction A+B+C→D+E, the initial reaction rate was measured for various initial concentrations of reactants. The followin

erastovalidia [21]

Answer : The initial rate for a reaction will be $3.4\times 10^{-3}Ms^{-1}$

Explanation :

Rate law is defined as the expression which expresses the rate of the reaction in terms of molar concentration of the reactants with each term raised to the power their stoichiometric coefficient of that reactant in the balanced chemical equation.

For the given chemical equation:

$A+B+C\rightarrow D+E$

Rate law expression for the reaction:

$\text{Rate}=k[A]^a[B]^b[C]^c$

where,

a = order with respect to A

b = order with respect to B

c = order with respect to C

Expression for rate law for first observation:

$6.0\times 10^{-5}=k(0.20)^a(0.20)^b(0.20)^c$ ....(1)

Expression for rate law for second observation:

$1.8\times 10^{-4}=k(0.20)^a(0.20)^b(0.60)^c$ ....(2)

Expression for rate law for third observation:

$2.4\times 10^{-4}=k(0.40)^a(0.20)^b(0.20)^c$ ....(3)

Expression for rate law for fourth observation:

$2.4\times 10^{-4}=k(0.40)^a(0.40)^b(0.20)^c$ ....(4)

Dividing 1 from 2, we get:

$\frac{1.8\times 10^{-4}}{6.0\times 10^{-5}}=\frac{k(0.20)^a(0.20)^b(0.60)^c}{k(0.20)^a(0.20)^b(0.20)^c}\\\\3=3^c\\c=1$

Dividing 1 from 3, we get:

$\frac{2.4\times 10^{-4}}{6.0\times 10^{-5}}=\frac{k(0.40)^a(0.20)^b(0.20)^c}{k(0.20)^a(0.20)^b(0.20)^c}\\\\4=2^a\\a=2$

Dividing 3 from 4, we get:

$\frac{2.4\times 10^{-4}}{2.4\times 10^{-4}}=\frac{k(0.40)^a(0.40)^b(0.20)^c}{k(0.40)^a(0.20)^b(0.20)^c}\\\\1=2^b\\b=0$

Thus, the rate law becomes:

$\text{Rate}=k[A]^2[B]^0[C]^1$

Now, calculating the value of 'k' by using any expression.

Putting values in equation 1, we get:

$6.0\times 10^{-5}=k(0.20)^2(0.20)^0(0.20)^1$

$k=7.5\times 10^{-3}M^{-2}s^{-1}$

Now we have to calculate the initial rate for a reaction that starts with 0.75 M of reagent A and 0.90 M of reagents B and C.

$\text{Rate}=k[A]^2[B]^0[C]^1$

$\text{Rate}=(7.5\times 10^{-3})\times (0.75)^2(0.90)^0(0.90)^1$

$\text{Rate}=3.4\times 10^{-3}Ms^{-1}$

Therefore, the initial rate for a reaction will be $3.4\times 10^{-3}Ms^{-1}$

8 0

3 years ago

Susan needs to measure and heat the chemical she wants to use in an experiment with a graduated cylinder. Which graduated cylind

Brut [27]

I think the best answer from the choices listed above is option B. The best graduated cylinder for this case is the glass cylinder. A metal cylinder is not possible because you cannot measure really since metals are not transparent. A plastic cylinder cannot also be used since the substance should be heated for the experiment.

6 0

3 years ago

Read 2 more answers

How does a magnet separate mixtures like sand and iron filings?​

How does a magnet separate mixtures like sand and iron filings?