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Andrei [34K]
3 years ago
5

Balance the chemical equation.Au plus HC l plus HNO 3 right arrow AuC l Subscript 3 Baseline plus NO plus Upper H 2 Upper OAu+HC

l+HNO3→AuCl3+NO+H2OAssume the coefficient ofUpper H 2 Upper OH2O is22. What is the balanced​ equation?nothing Au plus nothing HC l plus nothing HNO 3 right arrow nothing AuC l Subscript 3 Baseline plus nothing NO plus nothing Upper H 2 Upper O
Chemistry
1 answer:
tino4ka555 [31]3 years ago
5 0

Answer:

Au+ 3HCl + HNO_3 \to AuCl_3+NO+2H_2O

Explanation:

Chemical Equations are representations of chemical reactions in terms of the symbols and formulae of the elements and compounds involved. A chemical equation usually have the reactant at the left hand side while the product is on the right hand side.

A chemical Equation is of little or no value if is not in balanced equation. When an equation is balanced , the total number of atoms of any element on the left-hand side of it must be equal to the total number of atoms of that element on the right hand side.

in the given question; we are given a word problem of chemical symbol to  compute and also to balance the chemical equation.

From below; the chemical equation can be written as:

Au+ HCl + HNO_3 \to AuCl_3+NO+2H_2O

From the above  equation we will notice  that  it is not truly balanced ; so th balanced equation can be written as:

Au+ 3HCl + HNO_3 \to AuCl_3+NO+2H_2O

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Read 2 more answers
Consider 2 NOCl(g) \Longleftrightarrow⟺ 2 NO(g) + Cl2 (g) At 25oC under conditions other than equilibrium, there are 1.20 moles
nekit [7.7K]

Answer:

a) Q = 6.1875x10⁻³

b) The direction of the reaction is to form the products.

c) [Cl₂]e = 0.094 M

[NO]e =  0.190 M

[NOCl]e = 0.140 M

Explanation:

a) Q is the reaction quotient, and for a generic reaction aA + bB ⇄ cC + dD it is

Q = \frac{[C]^cx[D]^d}{[A]^ax[B]^b}

Which is the same equation for Kc, but in Kc expressions, the concentrations are in the equilibrium. Q is calculated at any time. So, for the reaction given

2NOCl(g) ⇄ 2NO(g) + Cl2(g)

Q = \frac{[Cl2]x[[NO]^2}{[NOCl]^2}

[Cl₂] = 0.220/5.00 = 0.044 M

[NO] = 0.450/5.00 = 0.090 M

[NOCl] = 1.20/5.00 = 0.240 M

Q = (0.044)x(0.090)²/(0.240)²

Q = 6.1875x10⁻³

b) Q < Kc, which means that there are fewer products to what are needed to the equilibrium. So the direction of the reaction is to form the products.

c)

2NOCl(g) ⇄ 2NO(g) + Cl2(g)

0.240           0.090      0.044         <em>Initial</em>

-2x                 +2x          +x             <em> Reacts</em> (stoichiometry is 2:2:1)

0.240-2x   0.090+2x   0.044+x    <em> Equilibrium</em>

Kc = \frac{(0.044+x)x(0.090+2x)^2}{(0.240 - 2x)^2}

1.86x10^{-1} = \frac{(0.044+x)*(8.1x10^{-3} +0.36x + 4x^2)}{(0.0576 - 0.96x +4x^2)}

3.564x10⁻⁴+0.01584x+0.176x²+8.1x10⁻³x+0.36x²+4x³ = 0.010714-0.17856x+0.744x²

4x³ - 0.208x² + 0.2025x - 0.01036 = 0

Solving this third grade equation in a computer program:

x = 0.05 M

So:

[Cl₂]e = 0.044 + 0.05 = 0.094 M

[NO]e = 0.090 + 2x0.05 = 0.190 M

[NOCl]e = 0.240 - 2x0.05 = 0.140 M

7 0
3 years ago
I NEED HELP PLEASE! :)
riadik2000 [5.3K]

Answer:

C_{21} H_{23} NO_{5}

Explanation:

First thing is we have assume all the percents are grams so we have

68.279g C, 6.2760g H, 3.7898g N, and 21.656g O

Now convert each gram to moles by dividing the the molar mass of each element

68.279g/12.01g= 5.685 moles of C

6.2760g/1.01g= 6.214 moles of H

3.7898g N/14.01g= 0.271 moles  of N

21.656g O/ 16.00g= 1.354 moles of O

Now to find the lowest ratios divide all the moles by the smallest number of moles you found, in our case, the smallest moles is 0.271 moles of N so divide everything by that....

5.685 moles/0.271 moles ------> ~21 C

6.214 moles/0.271 moles --------> ~23 H

0.271 moles  / 0.271 moles  ---------> 1 N

1.354 moles/ 0.271 moles ----------> ~5 O

So the empirical formula is C21H23NO5 C_{21} H_{23} NO_{5}

5 0
3 years ago
Convert 100 °C into Kelvin
Mice21 [21]

Hey there mate ;)!,

Given : 100°C

To convert to Kelvin scale unit,

Add the Celsius unit with 273.

→ (100+273) K

→<em><u> </u></em><em><u>373 </u></em><em><u>K</u></em>

<em>Therefore</em><em> </em><em>the </em><em>answer</em><em> is</em><em> </em><u>373 Kelvin</u><em> </em><em>or </em><u>373 </u><u>K.</u>

<em>By </em><em>Benjemin</em> ☺️

6 0
3 years ago
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