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Andrei [34K]
3 years ago
5

Balance the chemical equation.Au plus HC l plus HNO 3 right arrow AuC l Subscript 3 Baseline plus NO plus Upper H 2 Upper OAu+HC

l+HNO3→AuCl3+NO+H2OAssume the coefficient ofUpper H 2 Upper OH2O is22. What is the balanced​ equation?nothing Au plus nothing HC l plus nothing HNO 3 right arrow nothing AuC l Subscript 3 Baseline plus nothing NO plus nothing Upper H 2 Upper O
Chemistry
1 answer:
tino4ka555 [31]3 years ago
5 0

Answer:

Au+ 3HCl + HNO_3 \to AuCl_3+NO+2H_2O

Explanation:

Chemical Equations are representations of chemical reactions in terms of the symbols and formulae of the elements and compounds involved. A chemical equation usually have the reactant at the left hand side while the product is on the right hand side.

A chemical Equation is of little or no value if is not in balanced equation. When an equation is balanced , the total number of atoms of any element on the left-hand side of it must be equal to the total number of atoms of that element on the right hand side.

in the given question; we are given a word problem of chemical symbol to  compute and also to balance the chemical equation.

From below; the chemical equation can be written as:

Au+ HCl + HNO_3 \to AuCl_3+NO+2H_2O

From the above  equation we will notice  that  it is not truly balanced ; so th balanced equation can be written as:

Au+ 3HCl + HNO_3 \to AuCl_3+NO+2H_2O

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tatiyna

Answer:

The partial pressure of argon in the flask = 71.326 K pa

Explanation:

Volume off the flask = 0.001 m^{3}

Mass of the gas = 1.15 gm = 0.00115 kg

Temperature = 25 ° c = 298 K

Gas constant for Argon R = 208.13 \frac{J}{kg k}

From ideal gas equation P V = m RT

⇒ P = \frac{m R T}{V}

Put all the values in above formula we get

⇒ P = \frac{0.00115}{0.001} × 208.13 × 298

⇒ P = 71.326 K pa

Therefore, the partial pressure of argon in the flask = 71.326 K pa

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Answer:

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Explanation:

may this answer is helpful for you

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<u>Answer:</u>

density of solid = 4.5 g/cm³

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