Answer:
1.2,dibromoethane is the sha'awa .
Answer:

Explanation:
Hello,
In this case, we can first compute the heat required for such temperature increase, considering the molar heat capacity of water (75.38 J/mol°C):

Afterwards, the mass of ice that can be melted is computed by:

So we solve for moles with the proper units handling:

Finally, with the molar mass of water we compute the mass:

Best regards.
This problem is providing the initial volume and pressure of nitrogen in a piston-cylinder system and asks for the final pressure it will have when the volume increases. At the end, the answer turns out to be 2.90 atm.
<h3>Boyle's law</h3>
In chemistry, gas laws are used so as to understand the volume-pressure-temperature-moles behavior in ideal gases and relate different pairs of variables.
In this case, we focus on the Boyle's law as an inversely proportional relationship between both pressure and volume at constant both temperature and moles:

Thus, we solve for the final pressure by dividing both sides by V2:

Hence, we plug in both the initial pressure and volume and final volume in order to calculate the final pressure:

Learn more about ideal gases: brainly.com/question/8711877