Answer:
Rule 1: Drop mono for the first element. Rule 2: Drop all prefixes if the first element is H. Rule 3: Drop the second o in mono prior to a vowel. Rule 4: Drop the a in prefixes ending in a prior to a vowel.
Answer:
(a) 0.8 s
(b) t = 7.2 s
Explanation:
(a) Half life expression for second order kinetic is:
![t_{1/2}=\frac{1}{k[A_o]}](https://tex.z-dn.net/?f=t_%7B1%2F2%7D%3D%5Cfrac%7B1%7D%7Bk%5BA_o%5D%7D)
Where,
is the initial concentration = 1.0 M
k is the rate constant = 1.25 M⁻¹s⁻¹
So,

Half life = 0.8 s
(b) Integrated rate law for second order kinetic is:
![\frac{1}{[A_t]} = \frac{1}{[A]_0}+kt](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B%5BA_t%5D%7D%20%3D%20%5Cfrac%7B1%7D%7B%5BA%5D_0%7D%2Bkt)
Where,
is the final initial concentration
For 90% completion, 10% is left. so,
![[A_t]=\frac {10}{100}\times 1.0=0.1\ M](https://tex.z-dn.net/?f=%5BA_t%5D%3D%5Cfrac%20%7B10%7D%7B100%7D%5Ctimes%201.0%3D0.1%5C%20M)
So,

t = 7.2 s
It has 5 digits so the exponent of 10 will be 4:-
61,103 =
6.1103 x 10^4
B
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