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ivolga24 [154]
4 years ago
9

Which of the following acids is the weakest? The acid is followed by its ka value. A) HC2H302, 1.8 * 10-5 B) HIO, 23 x 10-11 OC)

HBrO, 23 10-9 OD) HCIO, 2.9 ~ 10-8 O ECOHCO2H 63 x 10-5
Chemistry
1 answer:
NemiM [27]4 years ago
3 0

Answer:

the weakest acid is B) HIO

Explanation:

pKa = - log Ka

the higher the value of pKa, the lower the dissociation, therefore, an acid will be stronger the lower its pKa.

a) HC2H3O2; Ka = 1.8 E-5

⇒ pKa1 = - Log (1.8 E-5) = 4.745

b) HIO;  Ka = 23 E-11

⇒ pKa2 = - Log ( 23 E-11 ) = 9.638

c) HBrO;  Ka = 23 E-9

⇒ pKa3 = - Log ( 23 E-9 ) = 7.638

d) HClO;  Ka = 2.9 E-8

⇒ pKa4 = - Log ( 2.9 E-8 ) = 7.537

e) HCO2H; Ka = 63 E-5

⇒ pKa5 = - Log ( 63 E-5 ) = 3.200

from the values pKa, we places the acids from the weakest to the least weak:

1) pKa2; HIO (weakest)

2) pKa3

3) pKa4

4) pKa1

5) pKa5

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Answer:

Both molarity and formality express concentration as moles of solute per liter of solution. Formality is a substance's total concentration in solution without regard to its specific chemical form. ... The formality of a solution is defined as the number of formula mass of any solute dissolved in 1 litre of solution.

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<u>Given:</u>

Volume of HCl = 150 ml

Molarity of HCl = 0.10 M

<u>To determine:</u>

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<u>Explanation:</u>

The molarity of a solution is the number of moles of a solute dissolved in a given volume

In this case:

Molarity of HCl = moles of HCl/volume of the solution

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Answer:

C_{21} H_{23} NO_{5}

Explanation:

First thing is we have assume all the percents are grams so we have

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Now convert each gram to moles by dividing the the molar mass of each element

68.279g/12.01g= 5.685 moles of C

6.2760g/1.01g= 6.214 moles of H

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Now to find the lowest ratios divide all the moles by the smallest number of moles you found, in our case, the smallest moles is 0.271 moles of N so divide everything by that....

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Answer:

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7 0
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