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1 year ago

Can someone fill this out pleaseee for me

Chemistry

1 answer:

Ganezh [65]1 year ago

5 0

Filling out the table below following the outlined order:

Calcium - symbol = Ca; Group =2; Period = 4; Ar = 134; Am =40.078u; Ph = solid; Density = 1.55; Bp = 1757K; Mp = 1115K.
Vanadium - symbol = V; Group =5; Period = 4; Ar = 197; Am =50.9415u; Ph = solid; Density = 6.11; Bp = 3680K; Mp = 2183K.
Manganese - symbol = Mn; Group =7; Period = 4; Ar = 127; Am = 54.938044u; Ph = solid; Density = 7.21; Bp = 2334K; Mp = 1519K.
Cobalt: - symbol = Co; Group =9; Period = 4; Ar = 125; Am =58.933195 u; Ph = solid; Density = 8.90; Bp = 3200K; Mp = 1768K.
Zinc: - symbol = Zn; Group = 12; Period = 4; Ar = 134; Am =65.38 u; Ph = solid; Density = 7.14; Bp = 1180K; Mp = 692.68K.
Arsenic: - symbol = As; Group = 15; Period = 4; Ar = 197; Am = 74.9216 u; Ph = solid; Density = 5.75; Bp = 889K; Mp = 889K.
Bromine: - symbol = Br; Group =17; Period = 4; Ar = 120; Am = 79.904 u; Ph = Liquid; Density = 3.1028; Bp = 332K; Mp = 265K.

<h3>Meaning of Element</h3>

An element can be defined as a substance that can not be broken down into simpler substances.

An element serves as a building blocks for compounds and mixtures.

In conclusion, each element and its property as requested in the table are given above.

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Answer:

1.023 J / g °C

Explanation:

m = 37.9 grams

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The equation relating these equation is;

H = mcΔT

making c subject of formulae;

c = H / mΔT

c = 969 J / (37.9 g * 25.0*C)

Upon solving;

c = 1.023 J / g °C

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Vinegar is a solution of acetic acid, CH3COOH, dissolved in water. A 5.54-g sample of vinegar was neutralized by 30.10 mL of 0.1

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Answer:

3.26 % of vinegar is acetic acid

Explanation:

Step 1: Data given

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Molarity of NaOH = 0.100M

Step 2: The balanced equation

CH3COOH + NaOH → CH3COONa + H2O

Step 3: Calculate moles NaOH

Moles NaOH = volume * molarity

Moles NaOH = 0.03010 L * 0.100M

Moles NaOH = 0.00301 moles NaOH

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For 1 mol NaOH we need 1 mol CH3COOH

For 0.00301 moles NaOH we nee 0.00301 moles CH3COOH

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Mass CH3COOH = 0.00301 moles * 60.05 g/mol

Mass CH3COOH = 0.1808 grams

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3.26 % of vinegar is acetic acid

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Alum is a compound used in a variety of applications including cosmetics, water purification, and as a food additive. It can be

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yield = 52.23 %

Explanation:

We have the following chemical reaction:

2 Al (s) + 2 KOH (aq) + 4 H₂SO₄ (aq) + 10 H₂O → 2 KAl(SO₄)₂·12 (H₂O) (s) + 3 H₂ (g)

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To calculate the theoretical quantity of alum that should be obtained from 0.03694 moles of aluminium we devise the following reasoning:

if 2 moles of aluminium produce 2 moles of alum

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reaction yield

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