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2 years ago

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A solid metal object hangs from a force sensor by a thread in the open air, and the actual weight is measured to be 0.71 N. Then

the object is lowered into a graduated cylinder of water until it is completely submerged but does not touch the bottom. The water level in the graduated cylinder measures 50 mL before the object is inserted and 75 mL after it's inserted. Predict the apparent weight of the object when submerged in water (the new force sensor reading).

1 answer:

Alexeev081 [22]2 years ago

5 0

Answer:

The apparent weight of the object is 0.465 N.

Explanation:

Given that,

Weight = 0.71 N

Water level = 50 mL

object inserted = 75 mL

We need to calculate the volume of solid

Using formula of volume

$V=25\ ml = 25\times10^{-6}\ m^3$

We need to calculate the buoyancy force

Using formula of buoyancy force

$F'= V\rho g$

Put the value into the formula

$F'=25\times10^{-6}\times1000\times9.8$

$F'=0.245\ N$

We need to calculate the apparent weight of the object

Using formula of apparent weight

$W=F-F'$

Put the value into the formula

$W=0.71-0.245$

$W=0.465\ N$

Hence, The apparent weight of the object is 0.465 N.

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