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Anika [276]
3 years ago
15

]\ \textless \ br /\ \textgreater \ \huge \boxed{ \red{φµεรƭเσɳ -}} \ \textless \ br /\ \textgreater \ ​ \ \textless \ br /\ \te

xtgreater \ \ \textless \ br /\ \textgreater \ [/tex]
\bold{ \sf{what \: is \:nitrogen \: fixation }}
​
Chemistry
2 answers:
Brums [2.3K]3 years ago
8 0

Nitrogen fixation is the incorporation of atmospheric nitrogen into ammonia by various bacteria, catalyzed by nitrogenase.This is an essential stage in the nitrogen cycle and is the ultimate source of all nitrogen in living organisms. Nitrogen cycle: atmospheric nitrogen is inert and cannot be used by living forms

<h3>Hope This Helps You ❤️</h3>
azamat3 years ago
6 0

Answer:

Nitrogen fixation is a chemical process by which molecular nitrogen in the air is converted into ammonia or related nitrogenous compounds in soil or aquatic systems. Atmospheric nitrogen is molecular dinitrogen, a relatively nonreactive molecule that is metabolically useless to all but a few microorganisms.

Explanation:

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Pls help me<br> what bond does not burn
patriot [66]

Answer:

Iconic bonds don't burn easily

Explanation:

Covalent bonds are non metals. Covalent bond (sharing), low temp, low temp, burn easily, poor, polar covalent is good and non-polar covalent is bad.

Ionic - metals and nonmetals, ionic bond is when electrons are gained or lost, high temp, high temp, doesn't burn easily, good, good

5 0
3 years ago
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What acid occurs naturally in the body and performs important regulatory functions
gtnhenbr [62]

Answer: carbonic acid

8 0
3 years ago
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Pls help will give brainliest
vlada-n [284]

The mass of a present which has a density of 2.15 kg/L and volume of 3650 mL is 7.74 kg.

<h3>How do we calculate mass?</h3>

Mass of any substance will be calculate by using the density and volume by using the below equation as:

Density = Mass / Volume

Given that,

Density of Christmas present = 2.15 kg/L

Volume of present = 3,650 mL = 3.6L

On putting values, we get

Mass = (2.15)(3.6) = 7.74

Hence required mass of Christmas present is 7.74 kg.

To know more about density, visit the below link:
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4 0
2 years ago
Compound has a molar mass of and the following composition: elementmass % carbon47.09% hydrogen6.59% chlorine46.33% Write the mo
snow_lady [41]

The given question is incomplete. The complete question is:

Compound X has a molar mass of 153.05 g/mol and the following composition:

element mass %

carbon 47.09%

hydrogen 6.59%

chlorine 46.33%

Write the molecular formula of X.

Answer: The molecular formula of X is C_6H_{10}Cl_2

Explanation:

If percentage are given then we are taking total mass is 100 grams.

So, the mass of each element is equal to the percentage given.

Mass of C= 47.09 g

Mass of H = 6.59 g

Mass of Cl = 46.33 g

Step 1 : convert given masses into moles.

Moles of C =\frac{\text{ given mass of C}}{\text{ molar mass of C}}= \frac{47.09g}{12g/mole}=3.92moles

Moles of H =\frac{\text{ given mass of H}}{\text{ molar mass of H}}= \frac{6.59g}{1g/mole}=6.59moles

Moles of Cl =\frac{\text{ given mass of Cl}}{\text{ molar mass of Cl}}= \frac{46.33g}{35.5g/mole}=1.30moles

Step 2 : For the mole ratio, divide each value of moles by the smallest number of moles calculated.

For C = \frac{3.92}{1.30}=3

For H = \frac{6.59}{1.30}=5

For Cl =\frac{1.30}{1.30}=1

The ratio of C : H: Cl= 3: 5 :1

Hence the empirical formula is C_3H_5Cl

The empirical weight of C_3H_5Cl = 3(12)+5(1)+1(35.5)= 76.5g.

The molecular weight = 153.05 g/mole

Now we have to calculate the molecular formula.

n=\frac{\text{Molecular weight }}{\text{Equivalent weight}}=\frac{153.05}{76.5}=2

The molecular formula will be=2\times C_3H_5Cl=C_6H_{10}Cl_2

7 0
3 years ago
A quantity of liquid methanol, CH3OH, is introduced intoa rigid 3.00-L vessel, the vessel is sealed, and the temperature israise
Tom [10]

Answer:

74,3 grams is the mass of methanol that was initially introduced into the vessel

Explanation:

                         CH3OH(g)        ---->          1 CO(g)    +   2 H2(g)

initial:             Idk what i have (X)                    -                    -

react:                initial - react                        react              react

equilibrium:    A concentration                  A conc.         0.426 M

                         in equilibrum                      in eq      

                         

See that in equilibrium are formed 2 moles of H2 with this concentration, 0,426M and you form 1 mol of CO, so the moles that are formed of H2 are the double of CO, because stoychiometry.

                            CH3OH(g)        ---->          1 CO(g)    +   2 H2(g)

initial:                 Idk what i have (X)                   -                    -

react:                    initial - react                     react              react

equilibrium:        A conc. in eq                     0,213 M         0.426 M

So we have concentrations of products in equilibrium, and we have Kc, now we can find concentration of reactants in equilibrium

Kc = ([CO] . [H2]*2) / [CH3OH]

6,9X10*-2 = (0,213 . 0,426*2) / [CH3OH]

[CH3OH] = (0,213 . 0,426*2) / 6,9X10*-2

[CH3OH] = 0,560 M

You know that 1 mol which reacted has this concentration in equilibrium, 0,213 M so I can know what's my initial concentration of reactive

Initial - react = equilibrium

initial - 0,213M = 0,560M ---> Initial = 0,773 M

0,773M is initial concentration of CH3OH, but this is molarity, (moles in 1L). My volume is 3 L so

1 L _____ 0,773 moles

3 L _____  3L . 0,773moles = 2,319 (the moles that i used)

Molar mass CH3OH = 32.06 g/m

Moles . molar mass = grams ---> 2,319 moles . 32,06 g/m  = 74,3 g                                                

8 0
3 years ago
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