Question

How much fluorine (in grams) did the second sample produce? ?Upon decomposition, one sample of magnesium fluoride produced 1.66 of magnesium and 2.56 of fluorine. A second sample produced 1.31 of magnesium.

Answer 1

Answer:

$\boxed{\text{2.02 g F}}$

Explanation:

You get 2.56 g of F with 1.66 g of Mg.

$\text{Mass of F} = \text{ 1.31 g Mg} \times \dfrac{\text{2.56 g F}} {\text{1.66 g Mg}} = \boxed{\textbf{2.02 g F}}$

Answer 2

Answer: The mass of fluorine produced in sample 2 will be 2.02 grams

Explanation:

The chemical formula of magnesium fluoride is $MgF_2$

We are given:

Mass of magnesium in sample 1 = 1.66 grams

Mass of fluorine in sample 1 = 2.56 grams

Mass of magnesium in sample 2 = 1.31 grams

Applying unitary method:

When 1.66 grams of magnesium is produced, the mass of fluorine produced is 2.56 grams

So, when 1.31 grams of magnesium will be produce, the mass of fluorine produced will be = $\frac{2.56}{1.66}\times 1.31=2.02g$

Hence, the mass of fluorine produced in sample 2 will be 2.02 grams