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3 years ago

#86 can an object be moving when its acceleration is zero? can an object be accelerating when its speed is zero?

1 answer:

7 0

Yes, an object that was set in motion in the past by some force, but that is no longer being acted on by a net force, is moving but with zero acceleration, i.e. it is moving at constant velocity.

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Use the circuit to answer the following questions.

Zanzabum

Answer:

1)ammeter

2)ised to check measure of current flow through a circuit

3)o.90 ambere

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3 years ago

John took 0.75 hours to bicycle to his grandmother's house, a distance of 4 km. What is his velocity?

ddd [48]

Answer:

5.3Km/hr

Explanation:

Velocity=Displacement/Time

D=4km;T=0.75hr

V=4/0.75=5.33..

6 0

2 years ago

A worker assigned to the restoration of the Washington Monument is checking the condition of the stone at the very top of the mo

Mnenie [13.5K]

Answer:

Your answer is: K.E = 8.3 J

Explanation:

If the height (h) = 169.2 meters (m) and the mass (m) is 0.005 kilograms (kg) the total energy will be kinetic energy which is equal to the potential energy.

K.E = P.E and also P.E equals to mgh

Then you substitute all the parameters into the formula ↓

P.E = 0.005 × 9.81 × 169.2

P.E = 8.2908 J

So your answer is 8.2908 but if you round it is K.E = 8.3

7 0

3 years ago

Three charges, each of magnitude 10 nC, are at separate corners of a square of edge length 3 cm. The two charges at opposite cor

FinnZ [79.3K]

Answer:

The force exerted by three charges on the fourth is $F_{resultant}=2.74\times10^{-5}\ \rm N$

Explanation:

Given:

The magnitude of three identical charges, $q=10\ \rm nC$
Length of the edge of the square a=3 cm
Magnitude of fourth charge ,Q=3 nC

According to coulombs Law the force F between any two charge particles is given by

$F=\dfrac{kQq}{r^2}$

where r is the radial distance between them.

Since the force acting on the charge particle will be in different directions so according to triangle law of vector addition

$F_{resultant}=\sqrt ((\dfrac{kQq}{L^2})^2+(\dfrac{kQq}{L^2} })^2)+\dfrac{kQq}{(\sqrt{2}L)^2}\\F_{resultant}=\dfrac{kQq}{L^2}(\sqrt{2}-\dfrac{1}{2})\\F_{resultant}=\dfrac{9\times10^9\times10\times10^{-10}\times3\times10^{-9}}{0.03^2}(\sqrt{2}-\dfrac{1}{2})\\F_{resultant}=2.74\times 10^{-5}\ \rm N$

5 0

3 years ago

Which of these results in kinetic energy of an object? position motion mass volume

Ray Of Light [21]

Answer:

motion

Explanation:

the motion causes static which is kinetic energy

3 0

2 years ago

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