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Kobotan [32]
2 years ago
6

As a freely falling object picks up downward speed, what happens to the power supplied by the gravitational force?.

Physics
1 answer:
siniylev [52]2 years ago
5 0

Answer:

As a freely falling object picks up downward speed. What happens to the power supplied by the gravitational force? Does it increase, decrease or stay the same? The power will increase because (Power=work/time; work=f(d); and F x d/t; FV).

Explanation:

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Accounts for about 70% of the mass-energy content of the universe. It acts in opposition to gravity.
Talja [164]
I think it’s b because gravity pulls down or tword and that says moving away I could be wrong but I think it’s b
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3 years ago
A step up transformer used in an automobile has a potential difference across the primary of 1800 V and a potential difference a
Zepler [3.9K]
Please don't use a car's ignition coil as an example. Let's just say it's an ordinary transformer. If you connect 1800 volts AC to one side of the transformer and you get 12 volts out of the other side, then the turns of wire are in the same ratio as the voltages ... 1800/12 = 150.
A car coil doesn't work like an ordinary transformer. In a car, you put 12-volt pulses into one side, and you get voltage out of the other side that's high enough to fire spark plugs and ignite gasoline.
So you've actually got the primary and secondary windings labeled in reverse in the question, and you're actually using it as a step-DOWN transformer.
5 0
3 years ago
A 2 cm tall object is placed 30cm in front of a concave mirror with focal length of 25 cm. What is the height of the image?
viktelen [127]

Answer:

- 10 cm

Explanation:

h_{o} = height of the object = 2 cm

h_{i} = height of the image

d_{o}  = distance of the object from the mirror = 30 cm  

f  = focal length of the mirror = 25 cm  

d_{i}  = image distance

using the mirror equation

\frac{1}{d_{o}} + \frac{1}{d_{i}} = \frac{1}{f}

\frac{1}{30} + \frac{1}{d_{i}} = \frac{1}{25}

d_{i} = 150 cm

using the equation

\frac{h_{i}}{h_{o}} = \frac{- d_{i}}{d_{o}}

\frac{h_{i}}{2} = \frac{- 150}{30}

h_{i} = - 10 cm

8 0
3 years ago
How can energy crisis be aberted?​
omeli [17]

Answer:

Try and depend more on renewable energy sources. Use products that are more energy efficient. Make use of lighting control measures. Maintain climate change

6 0
3 years ago
What is the charge on 1.0 kg of protons? (e = 1.60 × 10-19 c, mproton = 1.67 × 10-27 kg)?
Andru [333]
First, we need to find the number of protons, which is the total mass divided by the mass of one proton:
N= \frac{m}{m_p}= \frac{1.0 kg}{1.67 \cdot 10^{-27} kg}=6.0 \cdot 10^{26} protons

Then, the total charge is the number of protons times the charge of a  single proton:
Q=Ne = 6.0 \cdot 10^{26}\cdot 1.60 \cdot 10^{-19} C=9.6 \cdot 10^7 C
8 0
4 years ago
Read 2 more answers
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