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3 years ago

As a freely falling object picks up downward speed, what happens to the power supplied by the gravitational force?.

Physics

1 answer:

siniylev [52]3 years ago

5 0

Answer:

As a freely falling object picks up downward speed. What happens to the power supplied by the gravitational force? Does it increase, decrease or stay the same? The power will increase because (Power=work/time; work=f(d); and F x d/t; FV).

Explanation:

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it is seen that in a balloon filled with air,if we press one side of the balloon the other side bulges out.why is it so???

marshall27 [118]

When we apply pressure on the one side of balloon the other side bulges out due to the movement of gas to other side.

<h3>What happen when we press one side of the balloon?</h3>

If we press one side of the balloon, the other side bulges out because the gas that present on one side moves to the other side where there is no pressure. The body of balloon is elastic so when we apply pressure the other side bulges out.

So we can conclude that when we apply pressure on the one side of balloon the other side bulges out due to the movement of gas to other side.

Learn more about pressure here: brainly.com/question/25736513

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2 years ago

The Tambora volcano on the island of Sumbawa, Indonesia has been known to throw ash into the air with a speed of 625 m/s during

Cerrena [4.2K]

Answer:

About 1-3 km

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4 years ago

Critical thinking!!

Maslowich

Answer:

No there is no displacement observed so no work done

8 0

4 years ago

A driver enters a one-lane tunnel at 34.4 m/s. The driver then observes a slow-moving van 154 m ahead travelling (in the same di

navik [9.2K]

Answer:

Ans. B) 22 m/s (the closest to what I have which was 20.16 m/s)

Explanation:

Hi, well, first, we have to find the equations for both, the driver and the van. The first one is moving with constant acceleration (a=-2m/s^2) and the van has no acceletation. Let´s write down both formulas so we can solve this problem.

$X(van)=5.65t+154$

$X(driver)=34.4t+\frac{(-2)t^{2} }{2}$

or by rearanging the drivers equation.

$X(driver)=34.4t+t^{2}$

Now that we have this, let´s equal both equations so we can tell the moment in which both cars crashed.

$X(van)=X(driver)$

$5.65t+154=34.4t-t^{2}$

$0=t^{2} -(34.4-5.65)t+154$ $0=t^{2} -28.75t+154$

To solve this equation we use the following formulas

$t=\frac{-b +\sqrt{b^{2}-4ac } }{2a}$

Where a=1; b=-28.75; c=154

So we get:

$t=\frac{28.75 +\sqrt{(-28.75)^{2}-4(1)(154) } }{2(1)}=21.63s$ $t=\frac{28.75 -\sqrt{(-28.75)^{2}-4(1)(154) } }{2(1)}=7.12s$

At this point, both answers could seem possible, but let´s find the speed of the driver and see if one of them seems ilogic.

$V(driver)=V_{0} +at$ }

$V(driver)=34.4\frac{m}{s} -2\frac{m}{s^{2} } *(7.12s)=20.16\frac{m}{s}$ $V(driver)=34.4\frac{m}{s} -2\frac{m}{s^{2} } *(21.63s)=-8.86\frac{m}{s}$

This means that 21.63s will outcome into a negative speed, for that reason we will not use the value of 21.63s, we use 7.12s and if so, the speed of the driver when he/she hits the van is 20.16m/s, which is closer to answer A).

Best of luck

8 0

3 years ago

What structure on the south african coast has a range of 63 km and releases flashes every 30 seconds?

I am Lyosha [343]

Answer:

Cape Point lighthouse

Explanation:

The lighthouse is located South of Cape Town, at a point where boats turn to go around the tip of Africa.

The new lighthouse has the most powerful light of all the lighthouses in South Africa, with a power of 10 megacandelas. That's why it's being visible for up to 63 km around.

It's a very important lighthouse helping to conduct the traffic around dangerous waters where 2 oceans meet.

7 0

4 years ago