I think the answer would be letter B.
Answer:
The angular speed of the Crab nebula pulsar is 190.3 rad/s.
Explanation:
Given that,
Time T= 33 ms = 0.033 s
The angular speed is equal to the 2π divided by time period.
We need to calculate the angular speed of the Crab nebula pulsar
Using formula of angular speed

Where, T = time
= angular speed
Put the value into the formula


Hence, The angular speed of the Crab nebula pulsar is 190.3 rad/s.
Mass of base ball = 0.25kg
Time = t = 0.0075/s
Force = F = 18,500N
Impulse = J = ?
Formula = Impulse = Force x time
= 18,500x0.0075
= 138.75 N-S
Rounded: 140 kg
Answer:
28.3 kg
Explanation:
Assuming the ground is level, the normal force equals the weight.
N = mg
277 N = m × 9.8 m/s²
m = 28.3 kg