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Mkey [24]
3 years ago
9

a and b together can do a work in 10 days B and C together can do the same work in 15 days a b and c together can do the same wo

rk in 8 days then how many days can B alone do this work​
Mathematics
1 answer:
trasher [3.6K]3 years ago
4 0

Answer:

hauqvuauq shuavauvqsjahw w

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Is an estimate for the percent of a number always,sometimes or never greater than actual percent of the number
posledela
It would be sometimes because it can be 82.2% but if you round it the closest one would be 80% if it was 84.7% its closer to 85 so it would be 85% I hope I helped you out rate the answer if I got it right thanks!
3 0
3 years ago
Who walks at a faster rate: someone who walks 60ft in 10sec or someone who walks 42ft in 6sec
julia-pushkina [17]

Answer:

42 ft in 6 seconds

Step-by-step explanation:

The person whom walks a greater distance in lees time is faster

7 0
3 years ago
Solve 6 &gt;b÷ (-3). Graph the solution.<br> The solution is..
olchik [2.2K]

Answer:

b>-18

Step-by-step explanation:

inequality form:b>-18

interval notation:(-18,inf.)

8 0
2 years ago
nA car dealer who sells only late-model luxury cars recently hired a new salesperson and believes that this salesperson is selli
7nadin3 [17]

Answer:

The value of an appropriate test statistic for the car dealer to use is -4.

Step-by-step explanation:

The null hypothesis is:

H_{0} = 4600

The alternate hypotesis is:

H_{1} < 4600

The test statistic is:

t = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}

In which X is the sample mean, \mu is the value tested at the null hypothesis, \sigma is the standard deviation and n is the size of the sample.

In this problem:

X = 4100, \mu = 4600, \sigma = 500, n = 16

Then

t = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}

t = \frac{4100 - 4600}{\frac{500}{\sqrt{16}}}

t = -4

The value of an appropriate test statistic for the car dealer to use is -4.

8 0
3 years ago
I need help please.
Lina20 [59]
The 1st choice, the third and the fifth are correct
because 26/9 = 3
and 12/4 = 3
and 21/7 = 3
8 0
3 years ago
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