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3 years ago

I REALLY NEED HELP!!!!

Physics

1 answer:

Katarina [22]3 years ago

4 0

Answer:

400 Ns

Explanation:

Impulse = Change in momentum

i.e I = ΔP

So that,

Impulse experienced by Max = Change in Max's momentum

Change in Max's momentum = m(v - u)

Where m is the mass, v is the velocity after collision, and u is the velocity before collision.

m = 100.0 kg, v = 2.0 m/s, u = 6.0 m/s

Change in Max's momentum = 100 x (2 -6)

= -400 kg m/s

The negative sign shows that the change in momentum was against his direction of motion.

Impulse experienced by Max = 400 Ns.

Thus,

Max experienced an impulse of 400 Ns as a result of the collision.

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Answer:

Choice A: approximately $0.015\; \rm m^2$ , assuming that the two pistons are connected via some confined liquid to form a simple machine.

Explanation:

Assume that the two pistons are connected via some liquid that is confined. Pressure from the first piston:

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To achieve a force of $9.900 \times 10^3\; \rm N$ , the surface area of the second piston should be:

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3 years ago

What is the acceleration of an object that goes from 45m/s to 10 m/s in 5 seconds?

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Answer:

$\boxed {\boxed {\sf a= -7 \ m/s^2}}$

Explanation:

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$a= \frac {v_f-v_i}{t}$

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$v_f=10 \ m/s \\v_i= 45 \ m/s \\t= 5 \ s$

Substitute the values into the formula.

$a= \frac{ 10 \ m/s - 45 \ m/s}{5 \ s}$

Solve the numerator.

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Divide.

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