-- If the frequency of a wave is too high for our eyes to detect it ... but not <u>too too</u> high ... we call it an <em>ultraviolet </em>wave.
-- If the wave's frequency is even higher than that, we call it an <em>X-ray</em> wave.
-- If the wave's frequency is even higher than that, we call it a <em>Gamma Ray </em>wave.
Answer:
The upward buoyancy force on an object acts through the overall center of buoyancy, being the centroid of the displaced volume of fluid. The weight force on the object acts through its center of gravity.
Answer:
a) KA = 1.2 J
b) vB = 5.00 m/s
c) W = 6.30 J
Explanation:
m = 0.600 kg
vA = 2.00 m/s
KB = 7.50 J
a) KA = ?
b) vB = ?
c) W = ?
We can apply the folowing equations
K = 0.5*m*v²
and
W = ΔK = KB- KA
then
a) KA = 0.5*m*vA² = 0.5*(0.600 kg)*(2.00 m/s)²
⇒ KA = 1.2 J
b) KB = 0.5*m*vB² ⇒ vB = √(2*KB / m)
⇒ vB = √(2*7.50 J / 0.600 kg)
⇒ vB = 5.00 m/s
c) W = ΔK = KB- KA = (7.50 J) - (1.2 J)
⇒ W = 6.30 J
You must first convert minutes to seconds so 10*60=600
Then multiply the number of seconds by the speed so 600*2=1200 m
