Answer:
e = 1.21 mV
Explanation:
given,
length of rod = 10 m
height of drop = 4.89 m
Earth’s magnetic field = 12.4 µT
acceleration of gravity = 9.8 m/s²
velocity of the beam


v = 9.79 m/s
emf of the beam
e = B l v
e = 12.4 x 10⁻⁶ x 9.79 x 10
e = 1.21 x 10⁻³ V
e = 1.21 mV
Answer : The correct option is, (d) 4 times
Solution :
According to the Coulomb's law, the electrostatic force of attraction or repulsion between two charges is directly proportional to the product of the charges and is inversely proportional to the square of the distance between the the charges.
Formula used :

where,
F = electrostatic force of attraction or repulsion
= Coulomb's constant
and
are the charges
r = distance between two charges
First we have to calculate the force exerted between S and q when the distance between the charge is 1 unit and let us assumed that the charge be 'q'
..........(1)
Now we have to calculate the force exerted between S and p when the distance between the charge is 2 unit at the same charge.
...........(2)
Equation equation 1 and 2, we get


Therefore, the force exerted between S and q is 4 times the force exerted between S and p.
Answer:
F = 0.332 N in the east direction
Explanation:
Length, L = 7.7 cm = 7.7 * 0.01 = 0.077 m(along the north south)
Current, I = 3.45 A (northwards)
Magnetic field, B = 1.25 T (vertically upwards)
The magnitude of the force is given by, F = ILBsin90
F = 3.45 * 0.077 * 1.25 * 1
F = 0.332 N
The direction of the force is calculated using the Right Hand Thumb Rule:
It states that "Hold the wire carrying current in your right hand so that the thumb points along the wire in the direction of the current, then the fingers will encircle the wire in the direction of the lines of magnetic force."
Based on the Right Hand Thumb Rule, the magnetic force will act in the east direction