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otez555 [7]
3 years ago
7

Gravity pulls downward on a rock with a force of 800 N. If you pull upward on the rock with a force of 400 N, what is the total

force acting on the rock?
A. 400 N downward
B. 400 N upward
C. 1200 N downward
D. 1200 N upward
Physics
2 answers:
aleksley [76]3 years ago
6 0
A i believe srry if wrong
wel3 years ago
3 0
The answer is
a. 400 N downward
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The gravity between me (68 kg) and my laptop (0.91 kg)
zepelin [54]
If you mean gravitational force, then it is GMm/r^2, which is G(68)(.91)/ (the distance between you and the laptop), where G is the universal gravitational constant
4 0
3 years ago
Why centre of gravity of ring is out of its body
earnstyle [38]
There's no reason why the center of gravity must be in a place where
there is a any mass. 

The center of gravity is simply a LOCATION ... the place where the 
amount of mass in any direction from it is the same amount. 

For that matter, whenever you know the location of the center of gravity
for ANY object, you can always go in there and scoop our a tiny spherical
hole at that place.  Then the center of gravity won't move, but it will be in an
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Here are a few more points to ponder:

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-- The center of gravity of a party balloon is somewhere inside the balloon,
where there is no rubber.  If the balloon is spherical, then its center of gravity
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-- The center of gravity of a square is the center of the square, not on any
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-- The center of gravity of a triangle is the centroid of the triangle, not on any
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8 0
3 years ago
At launch a rocket ship weighs 4.5 million pounds. When it is launched from rest, it takes 8.00 s to reach 161 km/h; at the end
SpyIntel [72]

Answer:

5.590278\ m/s^2

7.74038461538\ m/s^2

178.888896 m

12790.56 m

Explanation:

t = Time taken

u = Initial velocity

v = Final velocity

s = Displacement

a = Acceleration

v=u+at\\\Rightarrow a=\dfrac{v-u}{t}\\\Rightarrow a=\dfrac{\dfrac{161}{3.6}-0}{8}\\\Rightarrow a=5.590278\ m/s^2

The acceleration is 5.590278\ m/s^2

v=u+at\\\Rightarrow a=\dfrac{v-u}{t}\\\Rightarrow a=\dfrac{\dfrac{1610}{3.6}-\dfrac{161}{3.6}}{60-8}\\\Rightarrow a=7.74038461538\ m/s^2

The acceleration is 7.74038461538\ m/s^2

s=ut+\dfrac{1}{2}at^2\\\Rightarrow s=0\times t+\dfrac{1}{2}\times 5.590278\times 8^2\\\Rightarrow s=178.888896\ m

Distance traveled in the first 8 seconds is 178.888896 m

s=ut+\dfrac{1}{2}at^2\\\Rightarrow s=\dfrac{161}{3.6}\times 52+\dfrac{1}{2}\times 7.74038461538\times 52^2\\\Rightarrow s=12790.56\ m

Distance traveled during 8-60 second interval is 12790.56 m

6 0
3 years ago
The quartz crystal used in an electric watch vibrates with a frequency of 32,768 Hz. What is the period of the crystal's motion?
Elan Coil [88]

Answer:

Time period, T=3.05\times 10^{-5}\ s

Explanation:

Given that,

The quartz crystal used in an electric watch vibrates with a frequency of 32,768 Hz, f = 32768 Hz

We need to find the period of the crystal's motion. The relationship between the frequency and the time period is given by :

T=\dfrac{1}{f}

T is the time period of the crystal's motion.

Time period is given by :

T=\dfrac{1}{32768}

T=3.05\times 10^{-5}\ s

So, the time period of the crystal's motion is 3.05\times 10^{-5}\ s. Hence, this is the required solution.

8 0
3 years ago
What are the main causes of the convention currents in the asthenosphere?
Tju [1.3M]
I think it is c density and temperature
8 0
3 years ago
Read 2 more answers
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