Answer:
Explanation:
Given that,
Electric field E=135V/m
Energy stored in 1m³of air=?
The energy stored in an electric field is given as
u = ½ εo E²
Where
U is the energy stored
εo is permissivity and it value is 8.85×10^-12C²/N..m²
And E is the electric field
Then,
U=½×8.85×10^-12×135²
U=8.06×10^-8J/m³
Then, the energy stored in 1m³ of air is 8.06×10^-8 J/m³
Answer:
power will three times decrease (one-third)
Explanation:
P = W / t
thus when work is constant, power is inversely proportional to time
so, when time is tripled, power is decreased to one-third
Answer:
Explanation:
Let m is the mass of both cars. The first car is moving with speed v and the other car is moving with speed 2v. The only force acting on both cars is the centripetal force.
For faster car on the road,
v = 2v
..........(1)
For the slower car on the road,
............(2)
Equation (1) becomes,
So, the frictional force required to keep the slower car on the road without skidding is one fourth of the faster car.
Answer:
The coefficient of static friction between the box and floor is, μ = 0.061
Explanation:
Given data,
The mass of the box, m = 50 kg
The force exerted by the person, F = 50 N
The time period of motion, t = 10 s
The frictional force acting on the box, f = 30 N
The normal force on the box, η = mg
= 50 x 9.8
= 490 N
The coefficient of friction,
μ = f/ η
= 30 / 490
= 0.061
Hence, the coefficient of static friction between the box and floor is, μ = 0.061
Answer:
27%
Explanation:
15.999 divided by 58.32 = .27433128
Move the decimal place over 2 places.
27%
