The minimum velocity of the Salmon jumping at the given angle is 12.3 m/s.
The given parameters;
- height of the waterfall, h = 0.432 m
- distance of the Salmon from the waterfall, s = 3.17 m
- angle of projection of the Salmon, = 30.8º
The time of motion to fall from 0.432 m is calculated as;
![h = v_0_y + \frac{1}{2} gt^2\\\\0.432 = 0 + (0.5\times 9.8)t^2\\\\0.432 = 4.9t^2\\\\t^2 = \frac{0.432}{4.9} \\\\t^2 = 0.088\\\\t = \sqrt{0.088} \\\\t = 0.3 \ s](https://tex.z-dn.net/?f=h%20%3D%20v_0_y%20%2B%20%5Cfrac%7B1%7D%7B2%7D%20gt%5E2%5C%5C%5C%5C0.432%20%3D%200%20%2B%20%280.5%5Ctimes%209.8%29t%5E2%5C%5C%5C%5C0.432%20%3D%204.9t%5E2%5C%5C%5C%5Ct%5E2%20%3D%20%5Cfrac%7B0.432%7D%7B4.9%7D%20%5C%5C%5C%5Ct%5E2%20%3D%200.088%5C%5C%5C%5Ct%20%3D%20%5Csqrt%7B0.088%7D%20%5C%5C%5C%5Ct%20%3D%200.3%20%5C%20s)
The minimum velocity of the Salmon jumping at the given angle is calculated as;
![X = v_0_x t\\\\3.17 = (v_0\times cos(30.8)) \times 0.3\\\\10.567 = v_0\times cos(30.8)\\\\v_0 = \frac{10.567}{cos(30.8)} \\\\v_0 = 12.3 \ m/s](https://tex.z-dn.net/?f=X%20%3D%20v_0_x%20t%5C%5C%5C%5C3.17%20%3D%20%28v_0%5Ctimes%20cos%2830.8%29%29%20%5Ctimes%200.3%5C%5C%5C%5C10.567%20%3D%20v_0%5Ctimes%20cos%2830.8%29%5C%5C%5C%5Cv_0%20%3D%20%5Cfrac%7B10.567%7D%7Bcos%2830.8%29%7D%20%5C%5C%5C%5Cv_0%20%3D%2012.3%20%5C%20m%2Fs)
Thus, the minimum velocity of the Salmon jumping at the given angle is 12.3 m/s.
Learn more here: brainly.com/question/20064545
Yes thats correct....becuase all of your weight is concentrated on a small area compared to the larger surface area of your feet!
is that what your question was?
Answer:
t = 0.714 s and x = 5.0 m
Explanation:
This is a projectile throwing exercise, in this case when the skater leaves the bridge he goes with horizontal speed
vₓ = 7.0 m / s
Let's find the time it takes to get to the river
y = y₀ + v_{oy} t - ½ g t²
the initial vertical speed is zero and when it reaches the river its height is zero
0 = y₀ + 0 - ½ g t²
t =
t = ra 2 2.5 / 9.8
t = 0.714 s
the distance traveled is
x = vₓ t
x = 7.0 0.714
x = 5.0 m
Answer:
The thinking distance depends on the reaction time of the driver which could can affected by alcohol, distractions and tiredness. A faster speed increases both thinking distance, increasing the total stopping distance.
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Answer:
1)Observe a phenomenon
2)Ask a question/ start inferring
3)Form a hypothesis
4)Create an experiment
5)Collect data
6)Compare results
7)Analyze
8)Report findings
9)Compare with other experiments