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goblinko [34]
3 years ago
6

Fill in the blank

Physics
2 answers:
-Dominant- [34]3 years ago
8 0
I think 40 trillion km
scZoUnD [109]3 years ago
4 0

Answer:

40 trillions

Explanation:

I am correct because I got it right on the test

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A proton of mass is released from rest just above the lower plate and reaches the top plate with speed . An electron of mass is
xenn [34]

Answer:

  v = √ 2e (V₂-V₁) / m

Explanation:

For this exercise we can use the conservation of the energy of the electron

At the highest point. Resting on the top plate

         Em₀ = U = -e V₁

At the lowest point. Just before touching the bottom plate

        Emf = K + U = ½ m v² - e V₂

Energy is conserved

         Em₀ = Emf

          -eV₁ = ½ m v² - e V₂

           v = √ 2e (V₂-V₁) / m

Where e is the charge of the electron, V₂-V₁ is the potential difference applied to the capacitor and m is the mass of the electron

3 0
4 years ago
WHY is it so important to include units when expressing numbers?
Natasha_Volkova [10]

Answer:

Without units, the results are unclear and it is hard to keep track of what each seperate measurement entails.

5 0
4 years ago
What is the molality of a solution that contains 54 grams of NaOH dissolved in 1.50 kg of water? (The molar mass of NaOH 40.00 g
expeople1 [14]

Answer:

0.900 mol/kg

Explanation:

Molality is moles of solute per kilograms of solvent.

Converting 54 grams of NaOH to moles:

54 g NaOH × (1 mol NaOH / 40.00 g NaOH) = 1.35 mol NaOH

So the molality is:

m = (1.35 mol) / (1.50 kg)

m = 0.900 mol/kg

8 0
4 years ago
dvanced photodiode detectors have a second light-emitting diode, operating at a wavelength of 2.0 × 10–7 m, to detect even small
ICE Princess25 [194]

Answer:

1.5\cdot 10^{15}Hz

Explanation:

The relationship between wavelength and frequency is given by:

c=f \lambda

where

c=3\cdot 10^8 m/s is the speed of light

f is the frequency

\lambda is the wavelength

In this problem, we know the wavelength:

\lambda=2.0\cdot 10^{-7} m

So we can re-arrange the formula above to find the frequency:

f=\frac{c}{\lambda}=\frac{3.0\cdot 10^8 m/s}{2.0\cdot 10^{-7} m}=1.5\cdot 10^{15}Hz

5 0
4 years ago
Consecutive resonances occur at wavelengths of 8 m and 4.8 m in an organ pipe closed at one end. What is the length of the organ
pashok25 [27]

Answer:

Length of the organ pipe is 6 meters.

Explanation:

Let resonance occur at wavelengths of 8 m at n and wavelength of 4.8 m at (n+2). We know that resonance occurs at,

L=n\dfrac{\lambda}{4}

L=n\dfrac{8}{4}

L = 2 n.................(1)

And,

L=(n+2)\dfrac{4.8}{4}

L=n\dfrac{8}{4}

2n=1.2n+2.4 (from equation (1))

n = 3

Put the value of n in equation (1). So,

L=2\times 3=6\ m

So, the length of the organ pipe is 6 meters. Hence, this is the required solution.

8 0
4 years ago
Read 2 more answers
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