Answer:
Explanation:
Given that,
The length of a string, l = 0.87 m
Speed of the ball, v = 3.36 m/s
We need to find the acceleration of the ball. The acceleration acting on the ball is centripetal acceleration. It is given by :
So, the acceleration of the ball is .
Answer:
Based on the graph, the lepard was at about 15 m at 11 seconds, but since the dot is not directlty at 15 it is safe to just say the lepard was at 14 m at 11 seconds.
Answer:
The momentum principle tells us that impulse transfers momentum to an object. If an object has 2 kg m/s of momentum, a 1 kg m/s impulse delivered to the object increases its momentum to 3 kg m/s. That is, pfx = pix + Jx. Just as we did with energy, we can represent this “momentum accounting” with a momentum bar chart.
This problem involves Newton's universal law of gravitation and the equation to follow would be.
F = GM₁M₂/r²
Given: M₁ = 0.890 Kg; M₂ = 0.890 Kg; F = 8.06 x 10⁻¹¹ N; G = 6.673 X 10⁻¹¹ N m²/Kg²
Solving for distance r = ?
r = √GM₁M₂/F
r = √(6.673 x 10⁻¹¹ N m₂/Kg²)(0.890 Kg)(0.890 Kg)/ 8.06 x 10⁻¹¹ N
r = 0.81 m
Answer:
The water from head of 20m or above is brought in open or closed conduit. Traditionally wooden blades are used as turbine on which water jets are strike upon, jets rotates the bigger wheel mounted on smaller wheel. There is continuos feed of grains in between grinds into finer particles.