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miss Akunina [59]
4 years ago
15

A rigid uniform bar of length L and mass m is suspended by a massless wire AC and a rigid massless link BC. Determine the tensio

n in BC immediately after AC breaks.

Physics
1 answer:
Kobotan [32]4 years ago
5 0

Answer:

hello the needed diagram is missing attached below is the diagram and the detailed solution

The tension in BC = \frac{\sqrt{2} }{4} mg

Explanation:

ATTACHED BELOW IS THE DETAILED SOLUTION T THE GIVEN PROBLEM

Ma = mg - T/ \sqrt{2}  equation 1

Ma = 3T / \sqrt{2}   equation 2

equate both equations to determine the tension on BC

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The correct answer is C. Honesty regulated by a person’s sense of right and wrong.

Explanation:

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3 years ago
1. Calculate the power it takes for a 583 N student to climb up1.5 m stairs in 2.1 seconds. (find work first!)GivenFormulaSubsti
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Given data

*The given force is F = 583 N

*The given distance is s = 1.5 m

*The given time is t = 2.1 s

The formula for the power it takes for a 583 N student to climb up 1.5 m stairs in 2.1 seconds is given as

P=\frac{F\mathrm{}s}{t}

Substitute the known values in the above expression as

\begin{gathered} P=\frac{(583)(1.5)}{(2.1)} \\ =416.42\text{ W} \end{gathered}

Hence, the power it takes for a 583 N student to climb up 1.5 m stairs in 2.1 seconds is P = 416.42 W

3 0
2 years ago
An arrow of mass 0.5kg so it has 25J of kinetic energy; find the speed of the arrow v = m/s​
miss Akunina [59]

Answer:

10 m/s

Explanation:

Use the kinetic energy formula:

KE=(1/2)mv^2

I always remember it as Kevin is half-mad, and very square.

25J = (1/2)*0.5kg*(v^2)

50J = 0.5kg*(v^2)

100J = v^2

v = 10 m/s

Check it:

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