Its like weight but not. mass is the amount of matter in a substance.
Answer:
0.0010m SO₄²⁻
Explanation:
The freezing point depression due the addition of a solute into a pure solvent follows the equation:
ΔT = Kf×m×i (1)
<em>Where ΔT are °C that freezing point decreases (273.15K - 272.47K = 0.68K = 0.68°C). Kf is the constant of freezing point depression (1.86°C/m), m is molality of the solution (0.1778m) and i is Van't Hoff factor.</em>
Van't Hoff factor could be understood as in how many one mole of the solute (sulfuric acid, H₂SO₄), is dissociated.
H₂SO₄ dissociates as follows:
H₂SO₄ → HSO₄⁻ + H⁺
HSO₄⁻ ⇄ SO₄²⁻ + H⁺
<em>Not all HSO₄⁻ dissociates.</em>
1 Mole of H₂SO₄ dissociates in 1 mole of H⁺+ 1 mole of HSO₄⁻ + X moles of SO₄²⁻= 2 + X
Replacing in (1):
0.68°C = 1.86°C/m×0.1778m×i
2.056 = i
Moles of SO₄²⁻ are 2.056 - 2 = 0.056moles SO₄²⁻.
If 1 mole has a concentration of 0.1778m, 0.056moles are:
0.056moles ₓ (0.1778m / 1mole) =
<h3>0.0010m SO₄²⁻</h3>
2.1.695 isn’t a real number?? but if it’s like number two on a paper it would be 1.695 x 104 - 1.395 x 1015=-1239.645
Answer:
Volume of water it can hold 63000,000 cm³
Mass of water is 63000,000 g.
Explanation:
Given data:
Length of tank = 70.00 cm
Width of tank = 300.00 mm
Height of tank = 300.00 m
Volume of water it can hold = ?
Mass of water = ?
Solution:
First of all we will convert the units into same unit.
Width of tank = 300.00 mm × 1 cm / 10 mm = 30 cm
Height of tank = 300.00 m× 100 cm / 1 m = 30000 cm
Volume of water it can hold:
V = l×w×h
V = 70.00 cm × 30 cm × 30000 cm
V = 63000,000 cm³
Mass of water:
Density of water from literature = 1 g/cm³
d = m/v
1 g/cm³ = m/ 63000,000 cm³
m = 63000,000 g
