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Fantom [35]
1 year ago
15

What mass in kilograms of E85( d = 0.758 g/mL ) can be contained in a 13.0 gal tank?Express your answer to three significant fig

ures and include the appropriate units.
Chemistry
1 answer:
melamori03 [73]1 year ago
4 0

The mass in kilograms of E85 with density of 0.758 g/mL that can be contained in a 13.0 gallon tank is 2,869.34g.

<h3>How to calculate mass?</h3>

The mass of a substance can be calculated using the following formula:

Density = mass ÷ volume

According to this question, a substance E85 has a density of 0.758g/mlL and it contains 13.0gallon of liquid. The mass can be calculated as follows:

13 gallon can be converted to 3785.412 millilitres

mass = 0.758 × 3785.412

mass = 2,869.34g

Therefore, the mass in kilograms of E85 with density of 0.758 g/mL that can be contained in a 13.0 gallon tank is 2,869.34g.

Learn more about mass at: brainly.com/question/19694949

#SPJ1

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The pathway by which carbon is transferred from living organisms to the atmosphere is called:
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Answer:

cellular respiration

Explanation:

All exergonic processes produced in the cell, through which substances oxidize and chemical energy is released, are grouped under the name of cellular respiration, but to break down an organic molecule the cells employ, mainly dehydrogenations that can be carried carried out in the presence or absence of atmospheric O2 oxygen. There are therefore two types of breathing: aerobic respiration and anaerobic respiration. The latter also called fermentation.

Aerobic respiration  (oxidative phosphorylation)

- Use molecular O2.

- It degrades glucose to CO2 and H2O

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3 years ago
A 2.50 g sample of solid sodium hydroxide is added to 55.0 mL of 25 °C water in a foam cup (insulated from the environment) and
zlopas [31]

Answer:

37.1°C.

Explanation:

  • Firstly, we need to calculate the amount of heat (Q) released through this reaction:

<em>∵ ΔHsoln = Q/n</em>

no. of moles (n) of NaOH = mass/molar mass = (2.5 g)/(40 g/mol) = 0.0625 mol.

<em>The negative sign of ΔHsoln indicates that the reaction is exothermic.</em>

∴ Q = (n)(ΔHsoln) = (0.0625 mol)(44.51 kJ/mol) = 2.78 kJ.

  • We can use the relation:

Q = m.c.ΔT,

where, Q is the amount of heat released to water (Q = 2781.87 J).

m is the mass of water (m = 55.0 g, suppose density of water = 1.0 g/mL).

c is the specific heat capacity of water (c = 4.18 J/g.°C).

ΔT is the difference in T (ΔT = final temperature - initial temperature = final temperature - 25°C).

∴ (2781.87 J) = (55.0 g)(4.18 J/g.°C)(final temperature - 25°C)

∴ (final temperature - 25°C) = (2781.87 J)/(55.0 g)(4.18 J/g.°C) = 12.1.

<em>∴ final temperature = 25°C + 12.1 = 37.1°C.</em>

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How are distant regions of the universe similar to space near earth
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2 years ago
Acenapthalene has the empirical formula C6H5. A solution of 0.515 g of acenapthalene in 15.0 g CHCl3 boils at 62.5oC. The normal
german

Answer:

The molecular formula of an ascenapthalene is C_{12}H_{10}

Explanation:

\Delta T_b=K_b\times m

\Delta T_b=K_b\times \frac{\text{Mass of acenapthalene}}{\text{Molar mass of acenapthalene}\times \text{Mass of chloroform in Kg}}

where,

\Delta T_f =Elevation in boiling point = (62.5-61.7)^oC=0.8^oC

Mass of acenapthalene = 0.515 g

Mass of CHCl_3 = 15.0 g = 0.015 kg (1 kg = 1000 g)

K_b = boiling point constant = 3.63 °C/m

m = molality

Now put all the given values in this formula, we get

0.8^0C=3.67 ^oC/m\times \frac{0.515}{\text{Molar mass of acenapthalene}\times 0.015kg}

\text{Molar mass of acenapthalene}=155.7875 g/mol

Let the molecule formula of the Acenapthalene be C_{6n]H_{5n}

6n\times 12 g/mol+5n\times 1 g/mol=155.7875 g/mol

n = 2.0

The molecular formula of an ascenapthalene is C_{12}H_{10}

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