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bekas [8.4K]
2 years ago
12

Newton’s second law can be written using two formulas, what are they?

Chemistry
1 answer:
wariber [46]2 years ago
3 0

Answer:

In equation form, Newton's second law of motion is a=Fnetm a = F net m . This is often written in the more familiar form: Fnet = ma. The weight w of an object is defined as the force of gravity acting on an object of mass m. ... Friction is a force that opposes the motion past each other of objects that are touching.

Explanation:

have a nice day :)

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Definition of diameter?
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Answer:

a straight line passing from side to side through the center of a body or figure, especially a circle or sphere.

Explanation:

a straight line passing from side to side through the center of a body or figure, especially a circle or sphere.

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3 years ago
Name the noble gas atom that has the same electron configuration as each ion in the compound rubidium oxide
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In rubidium oxide - Rb₂O , the ions are Rb⁺ and O²⁻
Rb is a group one element with one valence electron. To become stable it loses its outer electron to gain a complete outer shell.
Electronic configuration of Rb is - 1s² 2s² 2p⁶ 3s² 3p⁶ 3d¹⁰ 4s² 4p⁶ 5s¹
Once it loses its valence electron the configuration is;
 - 1s² 2s² 2p⁶ 3s² 3p⁶ 3d¹⁰ 4s² 4p⁶ 
The noble gas with this configuration is Krypton - Kr

Oxygen electron configuration is 1s² 2s² 2p⁴
Once it gains 2 electrons the configuration is  - 1s² 2s² 3p⁶
The noble gas with this configuration is Neon - Ne
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3 years ago
Which of the following is not true?
WITCHER [35]
There r three fundamental forces in nature
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3 years ago
Find the empirical formula of the compound ribose, a simple sugar often used as a nutritional supplement. A 14.229 g sample of r
MakcuM [25]

Answer:

CH2O

Explanation:

Firstly, we need to convert the masses of the elements to percentage compositions. This can be done by placing the mass of each element over the total mass multiplied by 100% . We can start with carbon.

C = 5.692/14.229 * 100 = 40%

O = 7.582/14.229 * 100 = 53.29%

H = 0.955/14.229 * 100 = 6.71%

We then proceed to divide each percentage composition by their atomic mass of 12, 16 and 1 respectively.

C = 40/12 = 3.333

O = 53.29/16 = 3.33

H = 6.71/2 = 6.71

Dividing by the smaller value which is 3.33

C = 3.33/3.33 = 1

O = 3.33/3.33= 1

H = 6.71/3.33 = 2

The empirical formula of the compound ribose is CH2O

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