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fiasKO [112]
3 years ago
14

In the reaction ___h2+n2 ->2 NH3, what coefficient should be placed in front of H2 to balance the reaction?

Chemistry
2 answers:
Nataly_w [17]3 years ago
7 0
In order to balance this equation you need to count each element and how many of the individual elements are in the equation.
_H2+N2=2 NH3
You multiply the 2 (Which is the coefficient) by the 3 (which is the subscript) This would equal 6 which indicated there are 6 hydrogen atoms on the right side so the left side should also have 6 hydrogen atoms

The missing coefficient on the left side must multiple the 2 to become 6 hydrogen
Answer=3
Umnica [9.8K]3 years ago
7 0
The answer is 3, I just took the Test
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PLEASE HELP! Will give brainliest answer for the right answer! ||| The specific types and sequence of amino acids determine the
vovangra [49]
Amino acids are Proteins, 
Lipids are Fatty acids 
Nucleic acid which have nucleotides and, build RNA and DNA 
Starches are a cause of Carbohydrates, after lots of Polymers. 

So, therefore the answer is a)
8 0
4 years ago
What is the density of CHCL3 vapor at 1.00atm and 298K?
Advocard [28]

Answer:

4.8 g/mL is the density of chloroform vapor at 1.00 atm and 298 K.

Explanation:

By ideal gas equation:

PV=nRT

Number of moles (n)

can be written as: n=\frac{m}{M}

where, m = given mass

M = molar mass

PV=\frac{m}{M}RT\\\\PM=\frac{m}{V}RT

where,

\frac{m}{V}=d which is known as density of the gas

The relation becomes:

PM=dRT    .....(1)

We are given:

M = molar mass of chloroform= 119.5 g/mol

R = Gas constant = 0.0821\text{ L atm }mol^{-1}K^{-1}

T = temperature of the gas = 298K

P = pressure of the gas = 1.00 atm

Putting values in equation 1, we get:

1.00atm\times 119.5g/mol=d\times 0.0821\text{ L atm }mol^{-1}K^{-1}\times 298K\\\\d=4.88g/L

4.8 g/mL is the density of chloroform vapor at 1.00 atm and 298 K.

7 0
3 years ago
How many moles of iron in a sample that contains 7.91 x 10^23 atoms of iron?
____ [38]

Answer:

181.93

Explanation:

Now give me money!

8 0
3 years ago
What volume of product is produced when 20.0 Mg of liquid hydrogen reacts with
mihalych1998 [28]

Answer: The volume of product formed is 0.26 L

Explanation:

\text{Moles of solute}=\frac{\text{given mass}}\times{\text{Molar Mass}}    

\text{Moles of} H_2=\frac{0.02g}{2g/mol}=0.01moles

2H_2(l)+O_2(l)\rightarrow 2H_2O(g)

As O_2 is the the excess reagent, H_2 is the limiting reagent as it limits the formation of product.

According to stoichiometry :

2 moles of H_2 give = 2 moles of H_2O

Thus 0.01 moles of H_2 will give =\frac{2}{2}\times 0.01=0.01moles  of H_2O

According to ideal gas equation:

PV=nRT

P = pressure of gas = 101.325 kPa = 1 atm

V = Volume of gas = ?

n = number of moles = 0.01

R = gas constant =0.0821Latm/Kmol

T =temperature =40^0C=(40+273)K=313K

V=\frac{nRT}{P}

V=\frac{0.01mol\times 0.0821L atm/K mol\times 313K}{1atm}=0.26L

Thus the volume of product formed is 0.26 L

8 0
3 years ago
2. What pressure is required to compress 196.0 L of air at 1.00 atmosphere into a cylinder
damaskus [11]

Answer:

<h2>7.54 atm </h2>

Explanation:

The required pressure can be found by using the formula for Boyle's law which is

P_2 =  \frac{P_1V_1}{V_2}  \\

where

P1 is the initial pressure

P2 is the final pressure

V1 is the initial volume

V2 is the final volume

From the question we have

P_2 =  \frac{1 \times 196}{26}  =  \frac{196}{26}   \\ = 7.538461...

We have the final answer as

<h3>7.54 atm </h3>

Hope this helps you

3 0
2 years ago
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